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GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(a,2\dfrac{2}{5}:y\times1\dfrac{3}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y\times\dfrac{7}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y=\dfrac{7}{8}:\dfrac{7}{4}\\ \dfrac{12}{5}:y=\dfrac{1}{2}\\ y=\dfrac{12}{5}:\dfrac{1}{2}=\dfrac{24}{5}\\ b,3\dfrac{2}{5}:y:1\dfrac{1}{4}=2\dfrac{3}{5}\\ \dfrac{17}{5}:y:\dfrac{5}{4}=\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{5}:\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{13}\\ y=\dfrac{17}{13}\times\dfrac{5}{4}=\dfrac{85}{52}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(c,\dfrac{12}{5}-2\dfrac{2}{5}\times y=1\dfrac{1}{4}\\ \dfrac{12}{5}-\dfrac{12}{5}\times y=\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{12}{5}-\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{23}{20}\\ y=\dfrac{23}{20}:\dfrac{12}{5}\\ y=\dfrac{23}{48}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(2\dfrac{2}{5}-y:2\dfrac{3}{4}=1\dfrac{1}{2}\\ \dfrac{12}{5}-y:\dfrac{11}{4}=\dfrac{3}{2}\\ y:\dfrac{11}{4}=\dfrac{12}{5}-\dfrac{3}{2}\\ y:\dfrac{11}{4}=\dfrac{9}{10}\\ y=\dfrac{9}{10}\times\dfrac{11}{4}=\dfrac{99}{40}\\ b,1\dfrac{1}{4}+2\dfrac{1}{5}\times y=2\dfrac{3}{5}\\ \dfrac{5}{4}+\dfrac{11}{5}\times y=\dfrac{13}{5}\\ \dfrac{11}{5}\times y=\dfrac{13}{5}-\dfrac{5}{4}\\ \dfrac{11}{5}\times y=\dfrac{27}{20}\\ y=\dfrac{27}{20}:\dfrac{11}{5}=\dfrac{27}{44}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(c,2\dfrac{4}{5}-2\dfrac{1}{4}:y=\dfrac{3}{4}\\ \dfrac{14}{5}-\dfrac{9}{4}:y=\dfrac{3}{4}\\ \dfrac{9}{4}:y=\dfrac{14}{5}-\dfrac{3}{4}\\ \dfrac{9}{4}:y=\dfrac{41}{20}\\ y=\dfrac{9}{4}:\dfrac{41}{20}=\dfrac{45}{41}\\ c2,x:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\\ x:\dfrac{10}{3}=\dfrac{12}{5}+\dfrac{7}{10}\\ x:\dfrac{10}{3}=\dfrac{31}{10}\\ x=\dfrac{31}{10}\times\dfrac{10}{3}=\dfrac{31}{3}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
9 tháng 9 2023
\(\dfrac{2}{5}\) x y : \(\dfrac{7}{4}\) = \(\dfrac{7}{8}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{7}{8}\) x \(\dfrac{7}{4}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{49}{32}\)
y = \(\dfrac{49}{32}\) : \(\dfrac{2}{5}\)
y = \(\dfrac{245}{64}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
9 tháng 9 2023
2\(\dfrac{2}{5}\): y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}\): y x \(\dfrac{5}{4}\) = \(\dfrac{13}{5}\)
\(\dfrac{12}{5}\): y = \(\dfrac{13}{5}\): \(\dfrac{5}{4}\)
\(\dfrac{12}{5}\): y = \(\dfrac{52}{25}\)
y = \(\dfrac{12}{5}\): \(\dfrac{52}{25}\)
y = \(\dfrac{15}{13}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 7 2023
2: y \(\times\) \(\dfrac{3}{5}\) = \(\dfrac{9}{10}\)
2:y = \(\dfrac{9}{10}\) : \(\dfrac{3}{5}\)
2: y = \(\dfrac{3}{2}\)
y = 2 : \(\dfrac{3}{2}\)
y = \(\dfrac{4}{3}\)
\(\dfrac{5}{4}\) - \(\dfrac{2}{5}\) : y = 1
\(\dfrac{2}{5}\) : y = \(\dfrac{5}{4}\) - 1
\(\dfrac{2}{5}\): y = \(\dfrac{1}{4}\)
y = \(\dfrac{2}{5}\) : \(\dfrac{1}{4}\)
y = \(\dfrac{8}{5}\)
\(\dfrac{3}{4}\) \(\times\) ( \(\dfrac{7}{2}\) - y) = \(\dfrac{3}{2}\)
\(\dfrac{7}{2}\) - y = \(\dfrac{3}{2}\) : \(\dfrac{3}{4}\)
\(\dfrac{7}{2}\) - y = 2
y = \(\dfrac{7}{2}\) - 2
y = \(\dfrac{3}{2}\)
PP
0
17 tháng 5
Lớp học online hay j mà lắm giáo viên thế🤔🤔 Lớp học của tri thức à?
DM
1
T
17 tháng 9 2023
\(a,y+\dfrac{2}{3}=\dfrac{5}{2}\)
\(y=\dfrac{5}{2}-\dfrac{2}{3}\)
\(y=\dfrac{15}{6}-\dfrac{4}{6}\)
\(y=\dfrac{11}{6}\)
\(b,3\dfrac{4}{5}-y=\dfrac{18}{5}\)
\(y=3\dfrac{4}{5}-\dfrac{18}{5}\)
\(y=\dfrac{19}{5}-\dfrac{18}{5}\)
\(y=\dfrac{1}{5}\)
\(c,y-4\dfrac{5}{6}=2\dfrac{1}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{13}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{18}{6}\)
\(y=\dfrac{18}{6}+\dfrac{29}{6}\)
\(y=\dfrac{47}{6}\)
DP
0
H9
HT.Phong (9A5)
CTVHS
22 tháng 7 2023
a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)
\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)
\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)
\(\dfrac{1}{2}:y=\dfrac{125}{36}\)
\(y=\dfrac{1}{2}:\dfrac{125}{36}\)
\(y=\dfrac{18}{125}\)
b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)
\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)
\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)
\(y=\dfrac{1}{3}:\dfrac{1}{2}\)
\(y=\dfrac{2}{3}\)
c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)
\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)
\(y:\dfrac{1}{3}=\dfrac{7}{12}\)
\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)
\(y=\dfrac{7}{36}\)
`y : 3/5 - 1/5 = 1/2`
`y : 3/5 = 1/2 + 1/5`
`y : 3/5 = 5/10 + 2/10`
`y : 3/5 = 7/10`
`y = 7/10 xx 3/5`
`y= 21/50`
Vậy `y= 21/50`
\(y\div\dfrac{3}{5}-\dfrac{1}{5}=\dfrac{1}{2}\)
\(y\div\dfrac{3}{5}=\dfrac{1}{2}+\dfrac{1}{5}\)
\(y\div\dfrac{3}{5}=\dfrac{7}{10}\)
\(y=\dfrac{7}{10}\times\dfrac{3}{5}\)
\(y=\dfrac{21}{50}\)