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a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
Bài 1 :
a) \(...=5^5:5^4=5\)
b) \(...=7^8:7^9=\dfrac{1}{7}\)
c) \(...=2^{15}:\left(2^6.2^5\right)=2^{15}:2^{11}=2^4=16\)
d) \(...=3^{28}:3^{26}=3^2=9\)
Bài 2 :
a) \(...=3^2.3^3:3^4=3^5:3^4=3\)
b) \(...=10^9-10^9=0\)
c) \(...=5^{10}.5^{30}:5^{12}=5^{40}:5^{12}=5^{28}\)
a) 25.69+31.25-25.6
= 25.(69+31-6)
= 25.94
= 2350
b) 198:[130-(27-19)2]+20210
= 198:[130-82]+1
= 198:(130-64)+1
= 198:66+1
= 3+1
= 4
c) 520:[515.(15+10)]
= 520:[515.25]
= 520:(515.52)
= 520: 517
= 53
a) − 105 + − 25 + ( − 105 ) + 50
= 105 + 25 + ( - 105) + 50
= [105 + ( -105)] + ( 25 + 50 )
= 0 + 75 = 75
b) 465 + − 38 + − 465 − 12 − − 42
= 465 + ( - 38) + ( -465) – 12 – 42
= [ 465 + (- 465) ] – ( 12 + 42 )
= 0 – 54 = 0 + ( -54 ) = -54
c) 65. − 19 + − 19 .24 + − 19 .11
= ( - 19) . ( 65 + 24 + 11 )
= ( -19) . 100 = -1900
d) − 3 2 + 2 3 − − 5 2 + 4 3
= 9 + 8 – 25 + 64 = 56
a: \(=\dfrac{14-2+9}{32}\cdot\dfrac{4}{5}=\dfrac{21}{5}\cdot\dfrac{1}{8}=\dfrac{21}{40}\)
b: \(=10+\dfrac{2}{9}+2+\dfrac{3}{5}+6+\dfrac{2}{9}=18+\dfrac{47}{45}=\dfrac{857}{45}\)
c: \(=\dfrac{3}{10}-\dfrac{12}{5}+\dfrac{1}{10}=\dfrac{4}{10}-\dfrac{12}{5}=\dfrac{2}{5}-\dfrac{12}{5}=-2\)
d: \(=\dfrac{-25}{30}\left(\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)=\dfrac{-25}{30}\cdot1=-\dfrac{5}{6}\)
25 – (9 – 10) + (28 – 4)
= 25 - (-1) + 24
=25 + 1 + 24
= 50
Đáp án: A
a, 249 - 25 × 8 + 32 × 4
= 249 - 200 + 9 × 4
= 49 + 36
= 85
b,27 : { 480 : [(513 : 9 + 19 ) + 84 ]}
= 27 : { 480 : [(57 + 19) + 84 ]}
= 27 : { 480 : [76 + 84]}
= 27 : { 480 : 160}
= 27 : 3
= 9
c. 73 × 25 + 28 × 25 - 25
= 73 × 25 + 28 × 25 - 25 × 1
= 25 × (73 + 28 - 1)
= 25 × 100
= 2500
d. 2× 9 × 50 - 890
= (2 × 50) × 9 - 1
= 100 × 9 - 1
= 900 - 1
= 899
a)\(249-25\cdot8+3^2\cdot4\)
\(=249-200+9\cdot4\)
\(=49+36=85\)
b)\(27:\left\{480:\left[\left(513:9+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[\left(57+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[76+84\right]\right\}\)
\(=27:\left\{480:160\right\}\)
\(=27:3=9\)
c)\(73\cdot25+28\cdot25-25\)
\(=73\cdot25+28\cdot25-25\cdot1\)
\(=\left(73+28-1\right)\cdot25\)
\(=100\cdot25=2500\)
d)\(2\cdot9\cdot50-89^0\)
\(=2\cdot9\cdot50-1\)
\(=900-1=899\)