Số hạng còn lại là :

\(192430+137279=329709\)

Kết quả đúng của phép tính là :

\(329709+137279=466988\)

Đáp số : \(466988\)

Bài 2 :

\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< x< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)

\(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{4}< x< \dfrac{1}{48}-\dfrac{1}{16}+\dfrac{1}{6}\)

\(\dfrac{6-4-3}{12}< x< \dfrac{1-3+8}{48}\)

\(\dfrac{-1}{12}< x< \dfrac{6}{48}\)

\(\dfrac{-1}{12}< x< \dfrac{1}{3}\)

mà \(x\inℤ\)

\(\Rightarrow x\in\left\{0\right\}\)

1) 

a) \(2027^{2016}=\overline{...1};2023^{101}=\overline{...1}\)

\(\Rightarrow2027^{2016}-2023^{101}=\overline{.....0}⋮10\left(dpcm\right)\)

b) \(34^{2025}=\overline{...4}\Rightarrow34^{2025}-4=\overline{.....0}⋮10\left(dpcm\right)\)

c) \(38^{101}=38^{4.25}.38=\overline{\overline{...6}}.38=\overline{...4}\)

\(\Rightarrow38^{101}+2=\overline{.....6}⋮̸5\) (xem lại đề bài)

d) \(2^{4n+1}=2^{4n}.2=\overline{...6}.2=\overline{...2}\)

\(\Rightarrow2^{4n+1}+3=\overline{.....5}⋮5\left(dpcm\right)\)

e) \(7^n-1=\overline{...1}-1=\overline{.....0}⋮5\left(dpcm\right)\)

1.Theres a big bottle on the table

2.There are many chairs in the living room

3.Theres are four cats and a dog in my house

4.Theres a furniture in that room

5.theres an ice cream in the fridge

6.Theres some children in the yard

7.Theres a laptop,a mouse and two pens in my bag

8.There are many quiz programs on TV last night

9.There a theater near her house

10.There are many fans in the room

Chúc bạn học tốt nhé!

1.Mary played the piano while her parents watched Tv

2.She painted a picture while her brother did his homework

3.Jane baked a cake while her has decorated the house

4.They explored the city streets and took photographs all day

5.My sister was playing badminton while my brother is flying his kite

6.Ngoe had an meeting on Wednesday at 9.am

7.Quang read the science book all morning .

Chúc bạn học tốt nhé!

charwoman?

Theo TCDTSBN, ta có :

\(\dfrac{0,2x-0,3}{0,5}=\dfrac{3y-4}{7}=\dfrac{9y-4x-6}{2x+5}=\dfrac{20\left(0,2x-0,3\right)-3\left(3y-4\right)+9y-4x-6}{20.0,5-3.7+2x+5}=\dfrac{4x-6-9y+12+9y-4x-6}{2x-6}=0\)

\(\Rightarrow\left\{{}\begin{matrix}\dfrac{0,2x-0,3}{0,5}=0\\\dfrac{3y-4}{7}=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{0,3}{0,2}=\dfrac{3}{2}\\y=\dfrac{4}{3}\end{matrix}\right.\)

Vậy \(\left(x;y\right)=\left(\dfrac{3}{2};\dfrac{4}{3}\right)\)

a) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\)

\(\Rightarrow99^{20}< 9999^{10}\)

b)\(8^5=\left(2^3\right)^5=2^{15}\)

\(3.4^7=3.\left(2^2\right)^7=3.2^{14}>2.2^{14}=2^{15}\)

\(\Rightarrow8^5< 3.4^7\)