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\(\dfrac{63\times81}{135\times84}\text{=}\dfrac{3\times3\times7\times3\times3\times3\times3}{3\times3\times3\times5\times2\times2\times3\times7}\text{=}\dfrac{9}{20}\)
63x81/135x84=3x3x7x3x3x3x3/3x3x3x5x22x2x7=9/20
1111x5/1515x7=101x11x5/101x3x5x7=11/21
Hoặc 1111x5/1515x7=1111x5/303x5x7=1111/303x7=1111/2121=1111:101/2121:101=11/21
a) 123<X<133
Theo đề ta có: x là số lẻ và x chia hết cho 5
nên x = 125
b)
\(\dfrac{35\times50}{48\times75}=\dfrac{35x2}{48x3}=\dfrac{35}{72}\)
\(\dfrac{18}{3}=18:3=6\)
\(\dfrac{45}{9}=45:9=5\)
\(\dfrac{8}{8}=8:8=1\)
\(\dfrac{7}{1}=7:1=7\)
a) 8 × 5 × 9 = (8 × 5) × 9 = 40 × 9 = 360
b) 6 × 7 × 5 = (6 × 5) × 7= 30 × 7= 210
c) 6 × 4 × 25 = 6 × (4 × 25) = 6 × 100= 600
a: \(=\dfrac{32}{48}\cdot\dfrac{50}{75}=\dfrac{2}{3}\cdot\dfrac{2}{3}=\dfrac{4}{9}\)
b: \(=\dfrac{7\cdot9\cdot81}{27\cdot5\cdot84}=\dfrac{9\cdot81}{27\cdot3}\cdot\dfrac{7}{5\cdot28}=9\cdot\dfrac{1}{4\cdot5}=\dfrac{9}{20}\)
\(a,\dfrac{8\times4\times50}{48\times75}=\dfrac{2\times2\times2\times2\times2\times25}{2\times2\times2\times2\times3\times25\times3}=\dfrac{2\times2}{3\times3}=\dfrac{4}{9}\)
\(b,\dfrac{7\times9\times81}{9\times3\times5\times84}=\dfrac{7\times9\times9\times3\times3}{9\times3\times5\times7\times3\times4}=\dfrac{9}{5\times4}=\dfrac{9}{20}\)
