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là:
xy.(-8xy4) c) x3y.(-5y2 z) d) –x.(-3x3y)
a) \(3xy^3\left(-2x^2yz^3\right)=-6x^3y^4z^3\)
b) \(xy\left(-8xy^4\right)=-8x^2y^5\)
c) \(x^3y\left(-5y^2z\right)=-5x^3y^3z\)
d) \(-x\left(-3x^3y\right)=3x^4y\)
a: =5x^3-5x^2y+5x-2x^2y+2xy^2-2y
=5x^3-7x^2y+2xy^2+5x-2y
b: =(x^2-1)(x+2)
=x^3+2x^2-x-2
c: =1/2x^2y^2(4x^2-y^2)
=2x^4y^2-1/2x^2y^4
d: =(x^2-1/4)(4x-1)
=4x^3-x^2-x+1/4
e: =x^2-2x-35+(2x+1)(x-3)
=x^2-2x-35+2x^2-6x+x-3
=3x^2-7x-38
f) \(2\cdot5^2+3:71^0-54:3^3\)
\(=2\cdot25+3:1-54:27\)
\(=50+3-2\)
\(=51\)
h) \(5\cdot3^2-32:4^2\)
\(=5\cdot9-32:16\)
\(=45-2\)
\(=43\)
k) \(5^6:5^4+2^3\cdot2^2-1^{2017}\)
\(=5^2+2^5-1\)
\(=25+32-1\)
\(=56\)
n) \(23\cdot75+5^2\cdot10+5^2\cdot13+180\)
\(=23\cdot25\cdot3+25\cdot10+25\cdot13+180\)
\(=25\cdot\left(23\cdot3+10+13\right)+180\)
\(=25\cdot92+180\)
\(=2300+180\)
\(=2480\)
f: =2*25+3-54:27
=50+3-2
=51
h: =5*9-32:16
=45-2=43
k: =5^2+2^5-1
=25+32-1
=25+31=56
n: =23*75+25*23+180
=2300+180
=2480
a) (x2 – x) . (2x2 – x – 10)
= x2 . (2x2 – x – 10) – x. (2x2 – x – 10)
= x2 . 2x2 + x2 . (-x) + x2 .(-10) – [ x. 2x2 + x. (-x) + x. (-10)]
= 2x4 – x3 - 10x2 – (2x3 – x2 – 10x)
= 2x4 – x3 - 10x2 – 2x3 + x2 + 10x
= 2x4 + (– x3 – 2x3 ) + (-10x2 + x2 )+ 10x
= 2x4 – 3x3 - 9x2 + 10x
b) (0,2x2 – 3x) . 5(x2 -7x + 3)
= (0,2x2 . 5 – 3x . 5) . (x2 -7x + 3)
= (x2 – 15x). (x2 -7x + 3)
= x2 . (x2 -7x + 3) – 15x. (x2 -7x + 3)
= x2 . x2 + x2 . (-7x) + x2 . 3 – [ 15x3 + 15x.(-7x) + 15x.3]
= x4 – 7x3 + 3x2 – (15x3 – 105x2 + 45x)
= x4 – 7x3 + 3x2 – 15x3 + 105x2 – 45x
= x4 +(– 7x3 – 15x3 )+ (3x2 + 105x2) – 45x
= x4 – 22x3 + 108x2 – 45x
a)
\(-12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
\(=-12:\left(\dfrac{18}{24}-\dfrac{20}{24}\right)^2\)
\(=-12:\left(\dfrac{-1}{12}\right)^2\)
\(=-12:\dfrac{1}{144}\)
\(=-12\times\dfrac{144}{1}\)
\(=-1728\)
b)
\(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\left(4\times\dfrac{3}{4}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\left(3-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}\times\dfrac{6}{5}-17\)
\(=3-17\)
\(=-14\)
a)\(=-12:\left(-\dfrac{1}{12}\right)^2\)
\(=-12:\dfrac{1}{144}\)\(=-12.144=-1728\)
b)\(=\left(8:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\left(6-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\dfrac{11}{2}.\dfrac{6}{5}-17=\dfrac{33}{5}-17=\dfrac{33}{5}-\dfrac{85}{5}=-\dfrac{2}{5}\)
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