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\(\frac{3.5}{8.24}=\frac{3.5}{2^3.2^3.3}=\frac{1.5}{8.8.1}=\frac{5}{64}\)
\(\frac{2.14}{7.8}=\frac{2.7.2}{7.2^3}=\frac{1.7}{7.2}=\frac{1}{2}\)
\(\frac{3.7.11}{22.9}=\frac{1.7.11}{11.2.3}=\frac{1.7.1}{1.2.3}=\frac{7}{6}\)
\(\frac{8.5-8.2}{16}=\frac{8\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{1.3}{1.2}=\frac{3}{2}\)
\(\frac{11.4-11}{2-13}=\frac{11\left(4-1\right)}{-11}=\frac{11.3}{-11}=-3\)
Bài 17 (Sgk Toán 6 Trang 15)
a) 3.5/8.24=3.5:3/8.24:3=5/8.8=5/64.
b) 2.14/7.8=2.2.7/7.2^3=2.7/7.4=1/2.
c) 3.7.11/22.9=3.7.1/12.11.3^2=7/2.3=76.
d) 8.5−8.2/16=(8.5−8.2):8/16:8=5−2/2=32.
e) 11.4−11/2−13=11.4−11/−11=(11.4−11):11/−11:11=4−1/−1=−3/1=-3
a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)
b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)
d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)
\(\dfrac{-63}{72}=\dfrac{-7}{8}\)
\(\dfrac{20}{-140}=\dfrac{-1}{7}\)
\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)
\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)
\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)
a, \(\frac{8.5-8.2}{16}\)\(=\frac{40-16}{16}=\frac{24}{16}=\frac{3}{2}\)
b, \(\frac{11.4-11}{2-13}=\frac{44-11}{-11}=\frac{33}{-11}=-3\)
Chúc em học tốt!
a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
*Rút gọn :
`(8.5-8.2)/16=(8.(5-2))/(8.2)=(8.3)/(8.2)=3/2`
`(11.4-11)/(2-13)=(11.(4-1))/(-11)=(11.3)/(-1.11)=3/(-1)=-3`
*Quy đồng :
- Ta có : `-3=(-3)/1`
UCLN(2,1)=2
$\to\begin{cases} \dfrac32=\dfrac32\\\dfrac{-3}1=\dfrac{-6}2\end{cases}$
