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Vì
\(\frac{13}{27}\)= 0,481
\(\frac{16}{33}\)= 0,484
Nên :
\(\frac{13}{27}\)< \(\frac{16}{33}\)
\(\dfrac{1313}{1717}=\dfrac{101x13}{101x17}=\dfrac{13}{17}\)
\(\dfrac{131313}{171717}=\dfrac{10101x13}{10101x17}=\dfrac{13}{17}\)
Vậy \(\dfrac{1313}{1717}=\dfrac{131317}{171717}\)
\(\dfrac{1313}{1717}và\dfrac{131313}{171717}\\ \dfrac{1313}{1717}=\dfrac{13}{17}\\ \dfrac{131313}{171717}=\dfrac{13}{17}\\ \Rightarrow\dfrac{1313}{1717}=\dfrac{131313}{171717}\)
Ta có: \(\frac{1111}{9999}=\frac{1111:1111}{9999:1111}=\frac{1}{9}\)
\(\frac{111111}{999999}=\frac{111111:111111}{999999:111111}=\frac{1}{9}\)
Suy ra: \(\frac{1111}{9999}=\frac{111111}{999999}\) (cùng bằng \(\frac{1}{9}\))
Ta có :
\(\frac{1111}{9999}=\frac{1111:1111}{9999:1111}=\frac{1}{9}\)
\(\frac{111111}{999999}=\frac{111111:111111}{999999:999999}=\frac{1}{9}\)
Do \(\frac{1}{9}=\frac{1}{9}\)
\(\Rightarrow\frac{1111}{9999}=\frac{111111}{999999}\)
Vậy \(\frac{1111}{9999}=\frac{111111}{999999}\)
~ Ủng hộ nhé
so sánh phần bù:
ta thấy :1-12/13=1/13; 1-13/14=1/14
Vì 1/13>1/14 nên 12/13 < 13/14
ta có : 1-\(\frac{12}{13}\)= \(\frac{1}{13}\)
1-\(\frac{13}{14}\)= \(\frac{1}{14}\)
vì \(\frac{1}{13}\)> \(\frac{1}{14}\)nên \(\frac{12}{13}\)< \(\frac{13}{14}\)
chúc bạn học tốt !!!
Giải
Ta có: \(\frac{345}{691}\)< \(\frac{345}{690}\)
\(\frac{345}{690}\)= \(\frac{1}{2}\)= \(\frac{413}{826}\) \(\frac{1}{2}\)
\(\frac{413}{826}\)< \(\frac{413}{825}\)
Vậy \(\frac{345}{691}\)<\(\frac{413}{825}\)
Ta có: \(\frac{2012}{2011}=1-\frac{1}{2011}\)
\(\frac{2011}{2010}=1-\frac{1}{2010}\)
Vì \(\frac{1}{2011}>\frac{1}{2010}\)nên \(\frac{2012}{2011}>\frac{2011}{2010}\)
\(\Rightarrow\frac{2012}{2011}>\frac{2011}{2010}\)
203/141 có tử lớn hơn mẫu nên phân số 203/141 > 1
105/152 có tử bé hơn mẫu nên phân số 105/152 < 1
=> 105/ 152 < 1< 203/141
=> 105/152 < 203/141
Vậy...
Ta có :
\(\frac{1313}{9191}\)= \(\frac{1}{7}\)= \(\frac{11}{77}\)
\(\frac{1111}{7373}\)= \(\frac{11}{73}\)
Vì \(\frac{11}{77}\)< \(\frac{11}{73}\)( 77>73)
=> \(\frac{1313}{9191}\)> \(\frac{1111}{7373}\)
\(\frac{1313}{9191}=\frac{1}{7}=\frac{1.11}{7.11}=\frac{11}{77}\)
\(\frac{1111}{7373}=\frac{11}{73}\)
\(\Rightarrow\frac{11}{77}< \frac{11}{73}\Rightarrow\frac{1313}{9191}>\frac{1111}{7373}\)