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a: =>3/5-x+13/20=5/6
=>11/10-x=5/6
=>x=11/10-5/6=4/15
b: =>x=4/9+5/9=1
c: =>3/2-2x=16/3:8/3=2
=>2x=-1/2
=>x=-1/4
d: =>x+1,5=-5/8*8/5=-1
=>x=-2,5
a: =3/8-1/4
=3/8-2/8
=1/8
b: =-5/9+3/5-1/9+2/5
=-2/3+1
=1/3
c: =21/7*5/25=3/5
d: =3/4+11/10:(2/5-3/2)-1/9
=-13/36
`a)3/5+(-4/9)`
`=3/5-4/9`
`=27/45-20/45`
`=7/45`
`b)3/5+2/5 . 15/8`
`=3/5 + 30/40`
`=3/5+3/4`
`=12/20+15/20`
`=27/20`
`c)7/2 . 8/13 + 8/13 . (-5/2)`
`=8/13 . (7/2 +(-5)/2)`
`=8/13 . 1`
`=8/13`
`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`
`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`
`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`
`= -9/23 ( -5/17 + 22/17)+11+9/23`
`= - 9/23 . 1+11+9/23`
`=-9/23+11+9/23`
`=(-9/23+9/23)+11`
`=0+11`
`=11`
a: =27/45-20/45=7/45
b: =3/5+30/40
=3/5+3/4
=12/20+15/20
=27/20
c: =8/13(7/2-5/2+1)=8/13*2=16/13
d: =9/23*5/17-9/23*22/17+11+9/23
=-9/23+11+9/23
=11
Dài wa nên mk chỉ ghi đáp án thui nha
a, x=1
b,x=66
c,x=4
d,x=5/3
e,x=17/25
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
a) \(-\frac{5}{2}:\left(\frac{3}{4}-\frac{1}{2}\right)\)
= \(-\frac{5}{2}:\left(\frac{6}{8}-\frac{4}{8}\right)\)
= \(-\frac{5}{2}:\frac{2}{8}\)
=\(-\frac{5}{2}.\frac{8}{2}\)
=\(-\frac{40}{4}\)
=\(-10\)
b) \(2,8:\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\)
=> \(\frac{14}{5}:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\)
=> \(\left(\frac{1}{5}-3x\right)=\frac{14}{5}:\frac{7}{5}\)
=> \(\left(\frac{1}{5}-3x\right)=\frac{14}{5}.\frac{5}{7}\)
=> \(\frac{1}{5}-3x=2\)
=> \(3x=\frac{1}{5}-2\)
=> \(3x=-\frac{9}{5}\)
=> \(x=-\frac{9}{5}:3\)
=> \(x=-\frac{3}{5}\)
a) \(\frac{-5}{2}:\left(\frac{3}{4}-\frac{1}{2}\right)\\ =\frac{-5}{2}:\left(\frac{3}{4}-\frac{2}{4}\right)\\ =\frac{-5}{2}:\frac{1}{4}\\ =\frac{-5}{2}\cdot4=-10\)
b) \(2,8:\left(\frac{1}{5}-3x\right)=1\frac{2}{5}\\ \Rightarrow\frac{14}{5}:\left(\frac{1}{5}-3x\right)=\frac{7}{5}\\ \Rightarrow\frac{1}{5}-3x=\frac{14}{5}:\frac{7}{5}\\ \Rightarrow\frac{1}{5}-3x=\frac{14}{5}\cdot\frac{5}{7}\\ \Rightarrow\frac{1}{5}-3x=2\\ \Rightarrow3x=\frac{1}{5}-2\\ \Rightarrow3x=\frac{-9}{5}\\ \Rightarrow x=\frac{-9}{5}:3\\ \Rightarrow x=\frac{-9}{5\cdot3}=\frac{-3}{5}\)
Vậy \(x=\frac{-3}{5}\)