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125 : \(x\) = 22 - (-1)
125 : \(x\) = 4 + 1
125 : \(x\) = 5
\(x\) = 125 : 5
\(x\) = 25
18 - (\(x\) + 14) : 3 = 27
(\(x\) + 14) : 3 = 18 - 27
(\(x\) + 14) : 3 = - 9
\(x\) + 14 = - 9.3
\(x\) + 14 = -27
\(x\) = -27 - 14
\(x\) = - 41
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a)abc chia hết 27
=>abc chia hết 3 và 9
mà abc chia hết 9 thì 100% chia hết 3
mà abc chia hết 9=>(a+b+c) chia hết 9
=>(b+c+a=a+b+c) chia hết 9 => bca chia hết 3
=>bca chia hết 27
a ) vì abc chia hết cho 27
=> bca chia hết cho 27 ( hiển nhiên đúng )
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`#3107.101107`
a,
$2014^{15} . (2x - 60) = 2014^{16}$
$\Rightarrow 2x - 60 = 2014^{16} \div 2014^{15}$
$\Rightarrow 2x - 60 = 2014$
$\Rightarrow 2x = 2074$
$\Rightarrow x = 1037$
Vậy, `x = 1037`
b,
`x + 18 \div 3^2 = 5.4^2`
`\Rightarrow x + 18 \div 9 = 5.16`
`\Rightarrow x + 9 = 80`
`\Rightarrow x = 80 - 9`
`\Rightarrow x = 71`
Vậy, `x = 71`
c,
`7.(42 - x) = 5^3 + 134`
`\Rightarrow 7.(42 - x) = 125 + 134`
`\Rightarrow 7(42 - x) = 259`
`\Rightarrow 42 - x = 259 \div 7`
`\Rightarrow 42 - x = 37`
`\Rightarrow x = 42 - 37`
`\Rightarrow x = 5`
Vậy, `x = 5.`
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Thôi, để mk giải chi tiết cho, không lại bảo mk lười:
A=\(\dfrac{18}{26}+\dfrac{-5}{27}+\dfrac{-22}{86}+\dfrac{12}{39}+\dfrac{-32}{43}\)
A=\(\dfrac{9}{13}+\dfrac{-5}{27}+\dfrac{-11}{43}+\dfrac{4}{13}+\dfrac{-32}{43}\)
A=\(\left(\dfrac{9}{13}+\dfrac{4}{13}\right)+\left(\dfrac{-11}{43}+\dfrac{-32}{43}\right)+\dfrac{-5}{27}\)
A= 1+(-1)+\(\dfrac{-5}{27}\)
A=0+\(\dfrac{-5}{27}\)
A=\(\dfrac{-5}{27}\)
B=\(\dfrac{-10}{12}+\dfrac{8}{15}+\dfrac{-19}{56}+\dfrac{-3}{18}+\dfrac{28}{60}\)
B=\(\dfrac{-5}{6}+\dfrac{8}{15}+\dfrac{-19}{56}+\dfrac{-1}{6}+\dfrac{7}{15}\)
B=\(\left(\dfrac{-5}{6}+\dfrac{-1}{6}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)+\dfrac{-19}{56}\)
B= -1+1+\(\dfrac{-19}{56}\)
B=0+\(\dfrac{-19}{56}\)
B=\(\dfrac{-19}{56}\)
Ôi mỏi quá! Chúc bạn học tốt !
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a: \(27^{x-1}=9^2\)
\(\Leftrightarrow3^{3x-3}=3^4\)
=>3x-3=4
=>3x=7
hay x=7/3
b: \(32^9=2^{45}\)
\(18^{13}=\left(2\right)^{13}\cdot3^{26}\)
mà \(2^{32}< 3^{26}\)
nên \(32^9< 18^{13}\)
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1) Ta có: \(\left(-86-x\right)-\left(3+2x\right)=-4-15\)
\(\Leftrightarrow-86-x-3-2x+4+15=0\)
\(\Leftrightarrow-3x-70=0\)
\(\Leftrightarrow-3x=70\)
hay \(x=-\dfrac{70}{3}\)
Vậy: \(x=-\dfrac{70}{3}\)
2) Ta có: \(18+\left(-x\right)-\left(40-28\right)=-32-\left(-18\right)\)
\(\Leftrightarrow18-x-40+28+32-18=0\)
\(\Leftrightarrow-x+20=0\)
\(\Leftrightarrow-x=-20\)
hay x=20
Vậy: x=20
3) Ta có: \(-27-\left(-31+x\right)-25=-5-17\)
\(\Leftrightarrow-27+31-x-25+5+17=0\)
\(\Leftrightarrow-x+1=0\)
\(\Leftrightarrow-x=-1\)
hay x=1
Vậy: x=1
4) Ta có: \(-9-14-x+42-38=-5+13\)
\(\Leftrightarrow-x-19=8\)
\(\Leftrightarrow-x=27\)
hay x=-27
Vậy: x=-27
60-x=32-(18-27)
60-x=41
x=60-41
x=19
60-x= 32-(18-27)
60-x=41
x=60-41
x=29