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25.9-25.17/-8.80-.10=25.(9-17)/-8(80+10)=25.(-8)/-8.90=25/90=5/18
48.12-48.15/-3.270-3.30=48.(12-15)/-3(270+30)=48.-3/-3.300=48/300=4/25
thông cảm e mới học lớp 6 nên sai thì thôi còn chỗ -3 hay -8 là vì thay -2 lần trừ ra cộng
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\(=\dfrac{5^2\cdot2^9\cdot3^9\cdot2\cdot5+2^5\cdot2^3\cdot3^5\cdot5^3\cdot3^3}{5^2\cdot2^8\cdot3^8\cdot2\cdot5-2\cdot2^8\cdot3^8\cdot2^3\cdot5^3}\)
\(=\dfrac{5^3\cdot2^{10}\cdot3^9+5^3\cdot2^8\cdot3^8}{5^3\cdot2^9\cdot3^8-5^3\cdot2^{12}\cdot3^8}\)
\(=\dfrac{5^3\cdot2^8\cdot3^8\left(2^2\cdot3+1\right)}{5^3\cdot2^9\cdot3^8\left(1-2^3\cdot1\right)}=\dfrac{1}{2}\cdot\dfrac{13}{1-9}=-\dfrac{13}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Có: \(\dfrac{5^2.6^9.10+6^5.2^3.15^3}{5^2.6^8.10-2.6^8.10}=\dfrac{5^2.2^9.3^9.2.5+2^5.3^5.2^3.3^3.5^3}{5^2.2^8.3^8.2.5-2.2^8.3^8.2^3.5^3}\)
=\(\dfrac{2^{10}.3^95^3+2^8.3^8.5^3}{2^9.3^8.5^3-2^{12}.3^8.5^3}=\dfrac{2^8.3^8.5^3.\left(12+1\right)}{2^8.3^8.5^3\left(2-16\right)}\)
= \(\dfrac{12+1}{2-16}=\dfrac{-13}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5^2.6^9.10+6^5.2^3.15^3}{5^2.6^8.10-2.6^8.10^3}=\frac{5^2.2^9.3^9.2.5+2^5.3^5.2^3.5^3.3^3}{5^2.2^8.3^8.2.5-2.2^8.3^8.2^3.5^3}\)
\(=\frac{2^{10}.3^9.5^3+2^8.3^8.5^3}{2^9.3^8.5^3-2^{12}.3^8.5^3}=\frac{2^8.3^8.5^3\left(2^2.3+1\right)}{2^9.3^8.5^3\left(1-2^3\right)}\)
\(=\frac{13}{2.-7}=-\frac{13}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5^3.3^7}{25.9^4}=\frac{5^3.3^7}{5^2.\left(3^2\right)^4}=\frac{5^2.3^7.5}{5^2.3^8}=\frac{\left(5^2.3^7\right).5}{\left(5^2.3^7\right).3}=\frac{5}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{27^2.64.125}{25.9^3.5^4}\)
\(A=\frac{3^3.2^6.5^3}{5^2.3^6.5^4}\)
\(A=\frac{2^6.5^3}{5^6.3^3}\)
\(A=\frac{2^6}{5^3.3^3}\)
\(A=\frac{64}{125.27}=\frac{64}{3375}\)
\(\frac{25.9-25.7}{-8.30-8.10}=\frac{25\left(9-7\right)}{-8\left(30+10\right)}=\frac{25.2}{-8.40}=\frac{50}{-320}=-\frac{5}{32}\)