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`136 -4^2 : x=134`
`=> 136-16:x=134`
`=> 16:x= 136-134`
`=> 16:x=2`
`=>x=16:2`
`=>x=8`
__
`19-5(x-1)=4`
`=> 5(x-1)=19-4`
`=> 5(x-1) =15`
`=> x-1=15:5`
`=>x-1=3`
`=>x=3+1`
`=>x=4`
__
`257-(x^2-1) =177`
`=>x^2-1=257-177`
`=>x^2-1=80`
`=>x^2=80+1`
`=>x^2=81`
`=>x^2=(+- 9)^2`
`=> x= +- 9`
__
`(x^2-17) : 8=2^3`
`=> x^2 -17 = 8 * 8`
`=> x^2 -17= 64`
`=> x^2 =64+17`
`=>x^2=81`
`=>x^2=(+- 9)^2`
`=> x= +- 9`
136 - 4² : x = 134
4² : x = 136 - 134
8 : x = 2
x = 8 : 2
x = 4
--------
129 - 5(x - 1) = 4
5(x - 1) = 129 - 4
5(x - 1) = 125
x - 1 = 125 : 5
x - 1 = 25
x = 25 + 1
x = 26
------------
257 - (x² - 1) = 177
x² - 1 = 257 - 177
x² - 1 = 80
x² = 80 + 1
x² = 81
x = -9 hoặc x = 9
--------
(x² - 17) : 8 = 8
x² - 17 = 8 . 8
x² - 17 = 64
x² = 64 + 17
x² = 81
x = -9 hoặc x = 9
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a) =25,97+(6,54+103,46)
=25,97+110
=135,97
b)136x75+75x64
=75x(136+64)
=75x200
=15 000
c) (21/8+1/2):5/16
=(21/8+4/8)x16/5
=25/8x16/5
=10
d)3/17-4/5+14/17
=(3/17+14/17)-4/5
=1-4/5
=1/5
Bài 2:
a)720:\([41-(2x-5)]\)=120
41 - (2x-5) =720:120
41 - (2x-5) =6
2x-5 =41-6
2x-5 =35
2x =35+5
2x =40
x =40:2
x =20
b)2/3 x X +3/4=3
2/3 x X =3-3/4
2/3 x X =12/4-3/4
2/3 x X =9/4
x =9/4:2/3
x =9/4x3/2
x =27/8
c) x+0,34=1,19x1,02
x+0,34=1,2138
x =1,2138-0,34
x =0,8738
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ (ghi lại cái đề)
=>+ 3x-7=2
3x=2+7=9
x=3
+ 3x-7=-2
3x=-2+7=5
x=\(\frac{5}{3}\)
b/ (5x-10)2=100
=> +5x-10=10
5x=10+10=20
x=4
+ 5x-10=-10
5x=-10+10=0
x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(4x^3+12=120\)
=>\(4x^3=108\)
=>\(x^3=27=3^3\)
=>x=3
b: \(\left(x-4\right)^2=64\)
=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)
c: (x+1)^3-2=5^2
=>\(\left(x+1\right)^3=25+2=27\)
=>x+1=3
=>x=2
d: 136-(x+5)^2=100
=>(x+5)^2=36
=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
e: \(4^x=16\)
=>\(4^x=4^2\)
=>x=2
f: \(7^x\cdot3-147=0\)
=>\(3\cdot7^x=147\)
=>\(7^x=49\)
=>x=2
g: \(2^{x+3}-15=17\)
=>\(2^{x+3}=32\)
=>x+3=5
=>x=2
h: \(5^{2x-4}\cdot4=10^2\)
=>\(5^{2x-4}=\dfrac{100}{4}=25\)
=>2x-4=2
=>2x=6
=>x=3
i: (32-4x)(7-x)=0
=>(4x-32)(x-7)=0
=>4(x-8)*(x-7)=0
=>(x-8)(x-7)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)
k: (8-x)(10-2x)=0
=>(x-8)(x-5)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)
m: \(3^x+3^{x+1}=108\)
=>\(3^x+3^x\cdot3=108\)
=>\(4\cdot3^x=108\)
=>\(3^x=27\)
=>x=3
n: \(5^{x+2}+5^{x+1}=750\)
=>\(5^x\cdot25+5^x\cdot5=750\)
=>\(5^x\cdot30=750\)
=>\(5^x=25\)
=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+1\right)+\left(x+5\right)+\left(x+9\right)+...+\left(x+29\right)=136\)\(136\)
\(x+1+x+5+x+9+...+x+29=136\)
\(29.x+\left(1+2+3+4+...+29\right)=136\)
\(29.x+\left[\left(29+1\right).29:2\right]=136\)
\(29.x+435=136\)
\(29.x=136-435=-299\)
\(x=\frac{-299}{29}\)
Phần còn lại bn cứ làm tương tự như thek nha!
Gợi ý nè , phần còn lại có 998 x
Nhớ k cho mk nha!
Ta có:
a) ( x + 1 ) + ( x + 5 ) + ( x + 9 ) +...+ ( x + 29 ) = 136
=> x + 1 + x + 5 + x + 9 +...+ x + 29 = 136
=> ( x + x + x +...+ x ) + ( 1 + 5 + 9 +...+ 29 ) = 136
=> 8x + 120 = 136
=> x = ( 136 - 120 ) : 8 = 2
b) ( y + 2 ) + ( y + 4 ) + ( y + 6 ) +.....+ ( y + 1996 ) = 998 000
=> y + 2 + y + 4 + y + 6 +....+ y + 1996 = 998 000
=> ( y + y + y + .... + y ) + ( 2 + 4 + 6 + .... + 1996 ) = 998 000
=> 998y + 997 002 = 998 000
=> y = ( 998 000 - 997 002 ) : 998
=> y = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
ko ghi đề
\(=25,97+\left(6,54+103,46\right)\)
\(=25,97+110\)
\(=135,97\)
giúp tớ với ét o ét