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C1:
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-2\frac{5}{7}-2\frac{1}{3}\)
A = \(3\frac{5}{7}-2\frac{5}{7}+4\frac{2}{3}-2\frac{1}{3}\)
A = \(1+2\frac{1}{3}\)
A = \(1+\frac{7}{3}\)
A = \(\frac{10}{3}\)
C2:
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)
A = \(\frac{26}{7}+\frac{14}{3}-\frac{19}{7}-\frac{7}{3}\)
A = \(1+\frac{14}{3}-\frac{7}{3}=\frac{10}{3}\)
C1: Ta có: \(B=8\frac{1}{9}-3\frac{2}{7}+6\frac{8}{7}-3\frac{5}{7}\)
\(=8+\frac{1}{9}-\left(3+\frac{2}{7}\right)+6+\frac{8}{7}-\left(3+\frac{5}{7}\right)\)
\(=8+\frac{1}{9}-3-\frac{2}{7}+6+1+\frac{1}{7}-3-\frac{5}{7}\)
= \(\left(8-3+6+1-3\right)+\left(\frac{1}{9}-\frac{2}{7}+\frac{1}{7}-\frac{5}{7}\right)\)
\(=9+\left(\frac{-47}{63}\right)\)
\(=\frac{520}{63}\)
C2: Đổi hỗn số ra phân số rồi tính ( cj nghĩ thế )
a) (38 - 60) + (20 - 38)
= 38 - 60 + 20 - 38
= (38 - 38) + (-60 + 20)
= 0 - 40
= -40
b) 75 - (20 + 75)
= 75 - 20 - 75
= (75 - 75) - 20
= 0 - 20
= -20
c) 32 + (60 - 32)
= 32 + 60 - 32
= (32 - 32) + 60
= 0 + 60
= 60
d) (81 - 36) - (81 - 36)
= 81 - 36 - 81 + 36
= (81 - 81) + (-36 + 36)
= 0 + 0
= 0
e) (2 + 4 + 6 + 8) - (1 + 3 + 5 + 7)
= 2 + 4 + 6 + 8 - 1 - 3 - 5 - 7
= (2 - 1) + (4 - 3) + (6 - 5) + (8 - 7)
= 1 + 1 + 1 + 1
= 4
f) (1 + 3 + 5 + 7 + ... + 99) - (2 + 4 + 6 + 8 + ... + 100)
= 1 + 3 + 5 + 7 + ... + 99 - 2 - 4 - 6 - 8 - ... - 100
= (1 - 2) + (3 - 4) + (5 - 6) + (7 - 8) + ... + (99 - 100)
= -1 - 1 - 1 - 1 - ... - 1 (50 chữ số 1)
= -50
a) -12.(x - 5) + 7(3 - x) = 5
=> -12x + 60 + 21 - 7x = 5
=> -19x + 81 = 5
=> -19x = 5 - 81
=> -19x = -76
=> x = -76 : (-19)
=> x = 4
b) (x + 1) + (x + 2) + (x + 3) + ... + (x + 20) = 250
=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 20) = 250
=> 20x + 210 = 250
=> 20x = 250 - 210
=> 20x = 40
= > x = 40 : 20
=> x = 2
\(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(\Leftrightarrow-12x+60+21-7x=5\)
\(\Leftrightarrow-19x+81=5\)
\(\Leftrightarrow81-5=19x\)
\(\Leftrightarrow19x=76\)
\(\Leftrightarrow x=4\)
1) \(\frac{5}{8}.\frac{7}{3}-\frac{5}{2}.\frac{1}{8}=\frac{5}{8}.\frac{7}{3}-\frac{5}{8}.\frac{1}{2}=\frac{5}{8}\left(\frac{7}{3}-\frac{1}{2}\right)=\frac{5}{8}.\frac{11}{6}=\frac{55}{48}\)
2) \(\frac{21}{10}.\frac{3}{4}-\frac{21}{10}.\frac{3}{4}=\frac{21}{10}\left(\frac{3}{4}-\frac{3}{4}\right)=\frac{21}{10}.0=0\)
3) \(\frac{-4}{11}:\frac{-6}{11}=\frac{-4}{11}.\frac{-11}{6}=\frac{-4.\left(-11\right)}{11.6}=\frac{-4.\left(-1\right)}{1.6}=\frac{4}{6}=\frac{2}{3}\)
4)\(\frac{2}{7}.\frac{14}{3}-1=\frac{2.14}{7.3}-1=\frac{2.2}{1.3}-1=\frac{4}{3}-1=\frac{1}{3}\)
5)\(\frac{4}{7}:\left(\frac{1}{5}.\frac{4}{7}\right)=\frac{4}{7}:\frac{4}{35}=\frac{4}{7}.\frac{35}{4}=\frac{4.35}{7.4}=\frac{1.5}{1.1}=5\)
6) \(\frac{12}{7}.\frac{7}{4}+\frac{35}{11}:\frac{245}{121}=\frac{12.7}{7.4}+\frac{35}{11}.\frac{121}{245}=\frac{3.1}{1.1}+\frac{35}{11}.\frac{121}{245}=3+\frac{35}{11}.\frac{121}{245}=3+\frac{35.121}{11.245}=\frac{1.11}{1.7}=\frac{11}{7}\)
1, Ta có :
\(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)
\(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)
\(x+\frac{3}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{3}{5}\)
\(x=\frac{15}{10}-\frac{6}{10}\)
\(x=\frac{9}{10}\)
Vậy x = \(\frac{9}{10}\)
2, Ta có :
\(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)
\(\frac{3}{4}\div x=-\frac{5}{6}\)
\(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)
\(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)
\(x=-\frac{9}{10}\)
Vậy x = \(-\frac{9}{10}\)
C =1+2-3-4+5+6-7-8+.....+97+98-99-100
= ( 1 + 2 -3 -4 ) + ( 5+6-7-8 ) + ... + ( 97 + 98 -99-100)
= 4 + ( -4 ) + ... + ( -4) ( do có 25 số)
= 4 x25 = 100
A= 1 + 2 - 3 -4 + 5 + 6 -7 -8 + ... +97 +98 -99 -100 ( có: ( 100 - 1 ) : 1 + 1 = 100 )
A= ( 1 +2 - 3 - 4 ) + ( 5 + 6 - 7 -8 ) + ... ( 97 + 98 - 99 +100 ) ( có 100 : 4 = 25 cặp )
A= - 4 + -4 + -4 + ... + -4 ( có 25 số hạng )
A= ( -4 ) . 25
A= -100
tham khảo
\(10\frac{3}{7}-\left(2\frac{1}{8}+4\frac{3}{7}\right)\)
\(=10\frac{3}{7}-2\frac{1}{8}-4\frac{3}{7}\)
\(=\left(10-4\right)+\left(\frac{3}{7}-\frac{3}{7}\right)-\frac{17}{8}\)
\(=6-\frac{17}{8}\)
\(=\frac{48}{8}-\frac{17}{8}\)
\(=\frac{31}{8}=3\frac{7}{8}\)