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27 tháng 8 2017

a)\(\frac{5}{3}\)+ \(\left(\frac{-2}{7}\right)\)-(-1,2)

=\(\frac{5}{3}+\left(\frac{-2}{7}\right)+\frac{6}{5}\)                                          

=\(\frac{175+\left(-30\right)+126}{105}\)

=\(\frac{271}{105}\)

b) \(\frac{-4}{9}+\frac{-5}{6}-\frac{17}{4}\)

=\(\frac{-16+\left(-30\right)-153}{36}\)

=\(\frac{-199}{36}\)

14 tháng 12 2017

\(\frac{5}{3}+\left(\frac{-2}{7}\right)-\left(\frac{-6}{5}\right)\)

=\(\frac{-2}{7}-\left(\frac{5}{3}+\frac{-6}{5}\right)\)

=\(\frac{-79}{105}\)\(\frac{-2}{7}-\frac{7}{15}\)

23 tháng 8 2023

\(A=\left(7-\dfrac{3}{4}+\dfrac{1}{3}\right)-\left(6+\dfrac{5}{4}-\dfrac{4}{3}\right)-\left(5-\dfrac{7}{4}+\dfrac{5}{3}\right)\)

\(\Rightarrow A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)

\(\Rightarrow A=\left(7-6-5\right)-\dfrac{3}{4}-\dfrac{5}{4}+\dfrac{7}{4}+\dfrac{1}{3}+\dfrac{4}{3}-\dfrac{5}{3}\)

\(\Rightarrow A=-4-\dfrac{1}{4}+0\)

\(\Rightarrow A=-\dfrac{17}{4}\)

Cách 2 tính trong dấu ngoặc đơn của A, bạn tự tính nhé.

24 tháng 8 2023

A = -17/4

21 tháng 4 2021

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21 tháng 4 2021

a) (689 + 875) + 125

= 689 + (875 + 125)

= 689 + 1000 = 1689.

581 + (878 + 419)

= (581 + 419) = 878

= 1000 + 878 = 1878.

b)

\left(\dfrac{2}{7} + \dfrac{4}{9}\right)+\dfrac{5}{7} = \left(\dfrac{2}{7} + \dfrac{5}{7}\right)+\dfrac{4}{9} = \dfrac{7}{7} +\dfrac{4}{9} = 1 +\dfrac{4}{9} = 1\dfrac{4}{9};

\dfrac{17}{11}+\left( \dfrac{7}{15}+\dfrac{5}{11}\right) = \left(\dfrac{17}{11} + \dfrac{5}{11}\right)+\dfrac{7}{15}\,= \dfrac{22}{11} +\dfrac{7}{15} = 2 +\dfrac{7}{15} = 2\dfrac{7}{15}.

c) 5,87 + 28,69 + 4,13

= (5,87 + 4,13) + 28,69

= 10 + 28,69

= 38,69.

83,75 + 46,98 + 6,25

= (83,75 + 6,25) + 46,98

= 90 + 46,98

= 136,98.

19 tháng 10 2023

\(A=\left(3-\dfrac{1}{4}+\dfrac{3}{2}\right)-\left(5+\dfrac{1}{3}-\dfrac{5}{6}\right)-\left(6-\dfrac{7}{4}+\dfrac{2}{3}\right)\\ \Rightarrow A=3-\dfrac{1}{4}+\dfrac{3}{2}-5-\dfrac{1}{3}+\dfrac{5}{6}-6+\dfrac{7}{4}-\dfrac{2}{3}\\ \Rightarrow A=\left(3-5-6\right)-\left(\dfrac{1}{4}+\dfrac{7}{4}\right)+\left(\dfrac{3}{2}+\dfrac{5}{6}-\dfrac{2}{3}\right)\\ \Rightarrow A=-8-\dfrac{3}{2}+\dfrac{5}{3}\\ =-\dfrac{47}{6}.\\ B=0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)

\(\Rightarrow B=\left(0,5+0,4\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{5}{7}-\dfrac{4}{35}\right)+\dfrac{1}{41}\\ \Rightarrow B=\dfrac{9}{10}+\dfrac{1}{2}+\dfrac{3}{5}+\dfrac{1}{41}\\ \Rightarrow B=2+\dfrac{1}{41}\\ \Rightarrow B=\dfrac{83}{41}.\)

29 tháng 10 2023

-_-

Giải:

1) (-8/13:3/7+-5/13:3/7).(-4)3.|-3|/7

=[7/3.(-8/13+-5/13)].-192/7

=[7/3.(-1)].-192/7

=-7/3.-192/7

=64

2) 75%-(5/2+5/3)+(-1/2)2

=3/4-25/6+1/4

=(3/4+1/4)-25/6

=1-25/6

=-19/6

Chúc bạn học tốt!

30 tháng 4 2021

1) \(\left(\dfrac{-8}{13}:\dfrac{3}{7}+\dfrac{-5}{13}:\dfrac{3}{7}\right).\dfrac{\left(-4\right).|-3|}{7}\)

  = \(\left[\left(\dfrac{-8}{13}+\dfrac{-5}{13}\right):\dfrac{3}{7}\right].\dfrac{-64.3}{7}\)

  = \(\left[-1:\dfrac{3}{7}\right].\dfrac{-192}{7}\)

  = \(\dfrac{-7}{3}.\dfrac{-192}{7}\)

  =       \(64\)

 

2)  \(75\%-\left(\dfrac{5}{2}+\dfrac{5}{3}\right)+\left(-\dfrac{1}{2}\right)^2\)

  = \(\dfrac{3}{4}-\dfrac{25}{6}+\dfrac{1}{4}\)

  = \(\left(\dfrac{3}{4}+\dfrac{1}{4}\right)-\dfrac{25}{6}\)

  =          \(1-\dfrac{25}{6}\)

  =            \(\dfrac{-19}{6}\)

Chúc bạn học tốt !hihi

27 tháng 8 2017

a. \(\dfrac{5}{3}+\left(\dfrac{-2}{7}\right)-\left(-1.2\right)\)

= \(\dfrac{5}{3}-\dfrac{2}{7}+\dfrac{6}{5}\)

= \(\dfrac{175}{105}-\dfrac{30}{105}+\dfrac{126}{105}\)

= \(\dfrac{271}{105}\)

b.\(\dfrac{-4}{7}+\left(\dfrac{-5}{6}\right)-\dfrac{17}{4}\)

= \(\dfrac{-4}{9}-\dfrac{5}{6}-\dfrac{17}{4}\)

= \(\dfrac{-16}{36}-\dfrac{30}{36}-\dfrac{153}{36}\)

= \(\dfrac{-199}{36}\)

a: =11+3/4-6-5/6+4+1/2+1+2/3

=10+9/12-10/12+6/12+8/12

=10+13/12=133/12

b: \(=2+\dfrac{17}{20}-1-\dfrac{11}{15}+2+\dfrac{3}{20}\)

=3-11/15

=34/15

c: \(=\dfrac{31}{7}:\left(\dfrac{7}{5}\cdot\dfrac{31}{7}\right)\)

\(=\dfrac{31}{7}:\dfrac{31}{5}=\dfrac{5}{7}\)

d: \(=\dfrac{29}{8}\cdot\dfrac{36}{29}\cdot\dfrac{15}{23}\cdot\dfrac{23}{5}=\dfrac{9}{2}\cdot3=\dfrac{27}{2}\)

11 tháng 4 2022

a, = (58/9 + 7/11) - (40/9 - 26/11)

= 701/99 - 206/99

= 5

b, = 51/5 - 11/2 . 60/11 + 3 : 3/20

= 51/5 - 30 + 20

= -99/5 + 20

= 1/5

c, = 19/4 + (-0,37) + 1/8 + (-1,8) + (-2,5) + 37/12

= 219/50 + -67/40 + 7/12

= 1973/600

15 tháng 12 2021

\(a.=\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{5}{3}+\dfrac{3}{2}+\dfrac{7}{3}-\dfrac{5}{2}=\dfrac{1+3-5}{2}-\dfrac{2+5-7}{3}=\dfrac{-1}{2}\)

\(b.\left(\dfrac{3}{4}-1\dfrac{1}{6}\right)^2:\sqrt{\dfrac{25}{144}}=\left(-\dfrac{5}{12}\right)^2:\dfrac{5}{12}=\dfrac{5}{12}\)

15 tháng 12 2021

thanks nhìu

24 tháng 1 2022

=\(\left[\dfrac{\left(0,4.2\right)^5}{\left(0,4\right)^6}+\dfrac{2^9.2^6.3^8}{\left(3.2\right)^6.2^9}\right]=\left[\dfrac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}+\dfrac{2^6.3^8}{3^6.2^6}\right]\)

=\(\left[\dfrac{2^5}{0,4}+3^2\right]\)

=\(\left[80+9\right]=89\)

24 tháng 1 2022

\(\left[\dfrac{\left(2.0,4\right)^5}{0,4,0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^6.2^9}\right]\div\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)

\(=\left[\dfrac{2^5.0.4^5}{0,4.0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^{15}}\right]\div3^5\)

\(=\left[\dfrac{2^5}{0,4}+3^2\right]\div243\)

\(=80+\left(3^5\div3^2\right)\)

\(=80+3^3\)

\(=80+27\)

\(=107\)