a) 100 - 88 : 3 + 8 = ???
b) 99 + 16 - 18 + 30 = ???
c) 109 + 26 : 7 - 66 = ???
d) 199 - 26 : 10 + 60 = ???
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GN
GV Nguyễn Trần Thành Đạt
Giáo viên
10 tháng 8 2023
\(\dfrac{21}{36}-\left(-\dfrac{11}{30}\right)=\dfrac{7}{12}+\dfrac{11}{30}=\dfrac{7.5+11.2}{60}=\dfrac{57}{60}=\dfrac{19}{20}\\ ----\\\dfrac{-4}{8}+\left(-\dfrac{3}{10}\right)=\dfrac{-1}{2}-\dfrac{3}{10}=\dfrac{-1.5-3}{10}=\dfrac{-8}{10}=-\dfrac{4}{5}\\ ----\\ \dfrac{7}{12}-\left(-\dfrac{9}{20}\right)=\dfrac{7}{12}+\dfrac{9}{20}=\dfrac{7.5+9.3}{60}=\dfrac{62}{60}=\dfrac{31}{30}\\ ---\\ \dfrac{-2}{5}+\left(-\dfrac{11}{30}\right)=-\dfrac{2}{5}-\dfrac{11}{30}=\dfrac{-2.6-11}{30}=-\dfrac{29}{30}\)
NT
Nguyễn thành Đạt
CTVHS
25 tháng 2 2023
\(a.18\times85+9\times30\)
\(\text{=}1530+270\)
\(\text{=}1800\)
\(b.9\times13+9\times80+63\)
\(\text{=}117+720+63\)
\(\text{=}900\)
\(c.8\times11+16\times40+72\)
\(\text{=}88+640+72\)
\(\text{=}800\)
8 tháng 4 2022
a: =-231-16+75+25-9
=-240+100-16
=-140-16=-156
b: =231-17-77=231-94=137
d: =a+b+c-c-b+a=2a
23 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\dfrac{7}{5}\cdot\dfrac{8}{19}+\dfrac{7}{5}\cdot\dfrac{12}{19}-\dfrac{7}{5}\cdot\dfrac{1}{19}\)
`=`\(\dfrac{7}{5}\cdot\left(\dfrac{8}{19}+\dfrac{12}{19}-\dfrac{1}{19}\right)\)
`=`\(\dfrac{7}{5}\cdot\dfrac{19}{19}=\dfrac{7}{5}\cdot1=\dfrac{7}{5}\)
`b)`
\(-\dfrac{3}{5}\cdot\dfrac{5}{7}+\left(-\dfrac{3}{5}\right)\cdot\dfrac{3}{7}+\left(-\dfrac{3}{5}\right)\cdot\dfrac{6}{7}\)
`=`\(-\dfrac{3}{5}\cdot\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)\)
`=`\(-\dfrac{3}{5}\cdot\dfrac{14}{7}\)
`=`\(-\dfrac{3}{5}\cdot2=-\dfrac{6}{5}\)
`c)`
\(10\dfrac{2}{9}+\left(2\dfrac{2}{5}-7\dfrac{2}{9}\right)\)
`=`\(10\dfrac{2}{9}+2\dfrac{2}{5}-7\dfrac{2}{9}\)
`=`\(\left(10\dfrac{2}{9}-7\dfrac{2}{9}\right)+2\dfrac{2}{5}\)
`=`\(3+2\dfrac{2}{5}=\dfrac{27}{5}\)
`d)`
\(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)
`=`\(6\dfrac{3}{10}-3\dfrac{4}{7}-2\dfrac{3}{10}\)
`=`\(\left(6\dfrac{3}{10}-2\dfrac{3}{10}\right)-3\dfrac{4}{7}\)
`=`\(4-3\dfrac{4}{7}=\dfrac{3}{7}\)
VN
Võ Ngọc Phương
VIP
23 tháng 7 2023
a) \(\dfrac{7}{5}.\dfrac{8}{19}+\dfrac{7}{5}.\dfrac{12}{19}-\dfrac{7}{5}.\dfrac{1}{19}\)
\(=\dfrac{7}{5}.\left(\dfrac{8}{19}+\dfrac{12}{19}-\dfrac{1}{19}\right)\)
\(=\dfrac{7}{5}.1\)
\(=\dfrac{7}{5}\)
b) \(\dfrac{-3}{5}.\dfrac{5}{7}+\dfrac{-3}{5}.\dfrac{3}{7}+\dfrac{-3}{5}.\dfrac{6}{7}\)
\(=\dfrac{-3}{5}.\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)\)
\(=\dfrac{-3}{5}.2\)
\(=\dfrac{-6}{5}\)
c) \(10\dfrac{2}{9}+\left(2\dfrac{2}{5}-7\dfrac{2}{9}\right)\)
\(=\dfrac{92}{9}+\dfrac{12}{5}-\dfrac{65}{9}\)
\(=\dfrac{92}{9}-\dfrac{65}{9}+\dfrac{12}{5}\)
\(=3+\dfrac{12}{5}\)
\(=\dfrac{15}{5}+\dfrac{12}{5}\)
\(=\dfrac{27}{5}\)
d) \(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)
\(=\dfrac{63}{10}-\dfrac{25}{7}-\dfrac{23}{10}\)
\(=\dfrac{63}{10}-\dfrac{23}{10}-\dfrac{25}{7}\)
\(=4-\dfrac{25}{7}\)
\(=\dfrac{28}{7}-\dfrac{25}{7}\)
\(=\dfrac{3}{7}\)
Chúc bạn học tốt
6
1
ND
Nguyễn Đức Trí
VIP
10 tháng 8 2023
a) \(...=-246+301=55\)
b) \(...=-\dfrac{10}{9}+\dfrac{5}{12}=-\dfrac{40}{36}+\dfrac{15}{36}=-\dfrac{25}{36}\)
c) \(...=-\dfrac{3}{26}+\dfrac{24}{69}=-\dfrac{207}{1794}+\dfrac{624}{1794}=\dfrac{417}{1794}\)
VC
Vũ Cao Minh⁀ᶦᵈᵒᶫ ( ✎﹏IDΣΛ亗 )
CTV
VIP
20 tháng 2 2020
a) \(\left(-1\right)\left[5^2-\left(4^3\right)\right]=\left(-1\right)\left(25-64\right)=\left(-1\right)\left(-39\right)=39\)
b) \(71.64-32.\left(-7\right)+32.11=142.32+32.7+32.11\)
\(=32.\left(142+7+11\right)=32.\left(142+18\right)=32.160=5120\)
c) \(666-\left(-422\right)-100-88=666+422-100-88\)
\(=\left(666+422\right)-\left(100+88\right)=1088-188=900\)
d) \(23-501-343+61-257+16-499\)
\(=\left(23+61+16\right)-\left(501+499\right)-\left(343+257\right)\)
\(=100-1000-600=100-\left(1000+600\right)=100-1600=-1500\)
PN
28 tháng 7 2020
a,\(2,5.16,27.4+7,3=16,27.10+7,3=162,7+7,3=170\)
b,\(8.6.10+4.25.12+3.16.31+2.34.24=48.10+48.25+48.31+48.34\)
\(=48.\left(10+25+31+34\right)=48.100=4800\)
c,\(78.31+78.24+78.17+22.72=78\left(31+24+17\right)+22.72=78.72+22.72\)
\(=72.\left(78+22\right)=72.100=7200\)
d,\(102.67-34.51=102.67-17.102=102.\left(67-17\right)=102.50=5100\)
đéo hiểu thì cút nhé đéo ai khiến m trả lời cả . ngu thì nói ngu đi đừng bày đặt t ghét nhất là cái loại như m đấy ạ
PN
28 tháng 7 2020
Bài 2
a, \(1-\left(12,5+x-4,25\right):21,75=0\)
\(=>21,75-12,5-x+4,25=0\)
\(=>13,5-x=0=>x=13,5\)
b,\(x.101-x+72.99+72=21050\)
\(=>100x+72.100=21050\)
\(=>100\left(x+72\right)=21050\)
\(=>x+72=210,5\)\(=>x=138,5\)
c,\(151-2\left(x-6\right)=2227:17\)
\(=>151-2\left(x-6\right)=131\)
\(=>2\left(x-6\right)=20\)
\(=>2x=32=>x=16\)
d,\(\left(x+4\right)+\left(x+6\right)+\left(x+8\right)+...+\left(x+26\right)=210\)\(=>12x+\left(4+6+8+...+26\right)=210\)
\(=>12x+180=210=>12x=30\)
\(=>x=\frac{30}{12}=\frac{15}{6}=\frac{5}{2}\)
bài này có dư đc ko em
Chắc là có