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mik chỉ nêu cách lm
a) ((5*(191-109)))+((624-296)/4))
b)100*66+100*35
=100*(66+35)=
( 191 x 5 - 109 x 5 ) + ( 624 : 4 - 296 : 4 )
= [ ( 191 - 109 ) x 5 ] + [ ( 624 - 296 ) : 4 ]
= 82 x 5 + 82
= 82 x ( 5 + 1 )
= 82 x 6
= 492
( 45 + 75 ) x 66 + ( 75 + 45 ) x 35
= ( 45 + 75 ) x ( 66 + 35 )
= 120 x 101
= 12120
hok tốt
Đặt : \(A=\dfrac{4}{8\times11}+\dfrac{4}{11\times14}+...+\dfrac{4}{296\times299}\)
\(\dfrac{3\times A}{4}=\dfrac{3}{8\times11}+\dfrac{3}{11\times14}+...+\dfrac{3}{296\times299}\\ =\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+...+\dfrac{1}{296}-\dfrac{1}{299}\\ =\dfrac{1}{8}-\dfrac{1}{299}\\ A=\left(\dfrac{1}{8}-\dfrac{1}{299}\right)\times4:3=\dfrac{97}{598}\)
Ta đặt
\(A=\dfrac{4}{8\times11}+\dfrac{4}{11\times14}+....+\dfrac{4}{296\times299}\)
\(\dfrac{3}{4}A=\dfrac{3}{8\times11}+\dfrac{3}{11\times14}+....+\dfrac{3}{296\times299}\)
\(\dfrac{3}{4}A=\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+....+\dfrac{1}{296}-\dfrac{1}{299}\)
\(\dfrac{3}{4}A=\dfrac{1}{8}-\dfrac{1}{299}=\dfrac{291}{2392}\)
\(A=\dfrac{291}{2392}\div\dfrac{3}{4}\)
\(A=\dfrac{97}{598}\)
a: =(1-2-3+4)+(5-6-7+8)+...+(21-22-23+24)
=0+0+...+0
=0
b: =-7111+53+711-153=-6400-100=-6500
c: =-43(-1-296+296)=-43*(-1)=43
3(x-296)=75
x-296=75:3
x-296=25
x =25+296
x =321
Vậy x=321
Chúc bạn học tốt!
\(3\left(x-296\right)=75\)
\(\left(x-296\right)=75:3=25\)
\(x\) \(=25+296=321\)
\(\text{Hok tốt!}\)
\(\text{@Kaito Kid}\)