Cho phân số: 27/28 . Hãy viết phân số trên thành tổng của hai phân số tối giản có cùng mẫu số.
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\(\dfrac{10}{27}\) = \(\dfrac{3+7}{27}\) = \(\dfrac{3}{27}\) + \(\dfrac{7}{27}\) = \(\dfrac{1}{9}\) + \(\dfrac{7}{27}\)
\(\dfrac{10}{27}\) = \(\dfrac{1}{9}\) + \(\dfrac{7}{27}\)
\(\dfrac{10}{27}\) = \(\dfrac{6+4}{27}\) = \(\dfrac{6}{27}\) + \(\dfrac{4}{27}\) = \(\dfrac{2}{9}\) + \(\dfrac{4}{27}\)
\(\dfrac{10}{27}\) = \(\dfrac{9+1}{27}\) = \(\dfrac{9}{27}\) + \(\dfrac{1}{27}\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{27}\)
\(\dfrac{10}{27}\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{27}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
10/27: 1/27+7/27+2/27
13/12: 1/12+7/12+5/12
15/8:7/8+3/8+5/8
10/27 = 1/27+2/27+7/27
13/12 = 1/12+5/12+7/12
15/8 = 3/8+5/8+7/8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{7}{12}=\dfrac{3}{12}+\dfrac{4}{12}=\dfrac{1}{4}+\dfrac{1}{3}\)
\(\dfrac{13}{27}=\dfrac{9}{27}+\dfrac{4}{27}=\dfrac{1}{3}+\dfrac{4}{27}\)
\(\dfrac{7}{12}\) = \(\dfrac{1+6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{2}\)
\(\dfrac{7}{12}\) = \(\dfrac{3+4}{12}\) = \(\dfrac{3}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\)
\(\dfrac{13}{27}\) = \(\dfrac{1+12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{4}{9}\)
\(\dfrac{13}{27}\) = \(\dfrac{4+9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{1}{3}\)
\(\dfrac{13}{27}\) = \(\dfrac{6+7}{27}\) = \(\dfrac{6}{27}\) + \(\dfrac{7}{27}\) = \(\dfrac{2}{9}\) + \(\dfrac{7}{27}\)
![](https://rs.olm.vn/images/avt/0.png?1311)