| x + 2017 | - x 2017 = x
- | x + 2006 | - 2006 = x
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`#3107.101107`
A,
\(2\times32\times12+4\times6\times41+8\times27\times3\\ =24\times32+24\times41+24\times27\\ =24\times\left(32+41+27\right)\\ =24\times100\\ =2400\)
B,
\(\left(2006\times2005^{2016}-2005^{2016}\right)\div2005^{2017}\\ =\left[2005^{2016}\times\left(2006-1\right)\right]\div2005^{2017}\\ =\left(2005^{2016}\times2005\right)\div2005^{2017}\\ =2005^{2017}\div2005^{2017}\\ =1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\left(x-1\right)^{2006}\ge0\)
\(\left(2y-1\right)^{2016}\ge0\)
\(\left(x+2y-z\right)^{2017}\ge0\)
Mà \(\left(x-1\right)^{2016}+\left(2y-1\right)^{2016}\)\(+|x+2y-z|^{2017}\)
\(\Rightarrow\hept{\begin{cases}\left(x-1\right)^{2006}=0\\\left(2x-1\right)^{2016}=0\\|x+2y-z|^{2017}=0\end{cases}\Leftrightarrow\hept{\begin{cases}x-1=0\\2y-1=0\\x+2y-z=0\end{cases}}}\)
\(\Rightarrow\hept{\begin{cases}x=1\\2y=1\\1-1-z=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=1\\y=\frac{1}{2}\\z=2\end{cases}}}\)
Vậy ...
Ta có :
\(\left(x-1\right)^{2006}\ge0\)
\(\left(2y-1\right)^{2016}\ge0\)
\(\left|x+2y-z\right|^{2017}\ge0\)
Mà \(\left(x-1\right)^{2006}+\left(2x-1\right)^{2016}+\left|x+2y-z\right|^{2017}=0\)
Suy ra : \(\hept{\begin{cases}\left(x-1\right)^{2006}=0\\\left(2x-1\right)^{2016}=0\\\left|x+2y-z\right|^{2017}=0\end{cases}\Leftrightarrow\hept{\begin{cases}x-1=0\\2y-1=0\\x+2y-z=0\end{cases}}}\)
\(\Leftrightarrow\)\(\hept{\begin{cases}x=1\\2y=1\\1+1-z=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=1\\y=\frac{1}{2}\\z=2\end{cases}}}\)
Vậy \(x=1\)\(;\)\(y=\frac{1}{2}\) và \(z=2\)
Chúc bạn học tốt ~
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Làm
\(\frac{x+1}{2020}+\frac{x+2}{2019}+\frac{x+3}{2018}=\frac{x+4}{2017}+\frac{x+5}{2016}+\frac{x+6}{2015}\)
<=>\(\frac{x+2021}{2020}+\frac{x+2021}{2019}+\frac{x+2021}{2018}=\frac{x+2021}{2017}+\frac{x+2021}{2016}+\frac{x+2021}{2015}\)
<=>\(\left(x+2021\right)\left(\frac{1}{2020}+\frac{1}{2019}+\frac{1}{2018}-\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)
<=> x+2021=0
<=> x=-2021
Kl:......................
b, Làmmmmm
\(\frac{2-x}{2004}-1=\frac{1-x}{2005}-\frac{x}{2006}\)
<=> \(\frac{2006-x}{2004}=\frac{2006-x}{2005}+\frac{2006-x}{2006}\)
<=> \(\left(2006-x\right)\left(\frac{1}{2004}-\frac{1}{2005}-\frac{1}{2006}\right)=0< =>2006-x=0\)
<=> x=2006
Kl:..............
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
2017*4+2017*62+2017*35-2017
=2017*(4+62+35-1)
=2017*100
=201700
2006*42+2006*39+2006*21-2006*2
=2006*(42+39+21-2)
=2006*100
=200600
k mik đi
câu hỏi là j vậy?!?
Đề bài là Tìm x biết nha