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Ta có: 23/22 = \(1\frac{1}{22}\)= 1+1/22
24/23 = \(1\frac{1}{23}\)=1+1/23
Vì 1/22 > 1/23
Nên \(1\frac{1}{22}>1\frac{1}{23}\)
Vậy 23/22>24/23
\(\frac{24}{23}=1+\frac{1}{23}\)
\(\frac{23}{22}=1+\frac{1}{22}\)
Vì \(\frac{1}{23}< \frac{1}{22}\Rightarrow\frac{23}{22}< \frac{24}{23}\)
a)12/5<5/2
b)6/15>3/8
c)\(\frac{17}{18}<\frac{18}{19}\)
d) \(\frac{24}{23}\) < \(\frac{23}{22}\)
a) Ta có \(\dfrac{23}{27}>\dfrac{23}{29};\dfrac{23}{29}>\dfrac{22}{29}\)
Vậy \(\dfrac{23}{27}>\dfrac{22}{29}\)
b) Ta có \(\dfrac{15}{25}=1-\dfrac{2}{5}\)
\(\dfrac{25}{49}=1-\dfrac{24}{49}\)
Vì \(\dfrac{2}{5}=\dfrac{24}{60}< \dfrac{24}{49}\)
Vậy \(\dfrac{15}{25}>\dfrac{25}{49}\)
a) \(\dfrac{252525}{666666}=\dfrac{25.10101}{66.10101}=\dfrac{25}{66}\)
⇒\(\dfrac{25}{66}=\dfrac{252525}{666666}\)
b: \(\dfrac{23}{24}=1-\dfrac{1}{24}\)
\(\dfrac{24}{25}=1-\dfrac{1}{25}\)
mà \(-\dfrac{1}{24}>-\dfrac{1}{25}\)
nên \(\dfrac{23}{24}>\dfrac{24}{25}\)
a: \(\dfrac{25}{66}=\dfrac{252525}{666666}\)
b: \(\dfrac{23}{24}=1-\dfrac{1}{24}\)
\(\dfrac{24}{25}=1-\dfrac{1}{25}\)
mà \(-\dfrac{1}{24}< -\dfrac{1}{25}\)
nên \(\dfrac{23}{24}< \dfrac{24}{25}\)
A, 12/5 va 5/2
= 24/10 va 25/10
=> 24/10 < 25/10 hay 12/5 < 5/2
B, 6/15 va 3/8
= 48/120 va 45/120
=> 48/120 > 45/120 hay 6/15 > 3/8
C, 17/8 va 18/4
= 17/8 va 36/8
=> 17/8 < 38/8 hay 17/8 < 18/4
D, 24/23 va 23/22
= 528/506 va 529/506
=> 528/506 < 529/506 hay 24/23 < 23/22
\(\frac{23}{22}< \frac{24}{22}\)vì \(23< 24\)