K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
TC
5 tháng 5 2022
a)\(=\left(\dfrac{2}{2}+\dfrac{1}{2}\right)\times\left(\dfrac{3}{3}+\dfrac{1}{3}\right)\times...\times\left(\dfrac{2005}{2005}+\dfrac{1}{2005}\right)\)
\(=\dfrac{3}{2}\times\dfrac{4}{3}\times...\times\dfrac{2006}{2005}=\dfrac{2006}{2}=1003\)
b)\(=\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\times\dfrac{1}{2}=\dfrac{3}{3}\times\dfrac{1}{2}=\dfrac{1}{2}\)
C
18 tháng 4 2022
2/9 : 2/3 x 1/2 = 2/9 x 3/2 x 1/2 = 1/6
1/2 x 1/3 + 1/4 = 1/6 + 1/4 = 5/12
2/7 : 2/3 - 1/7 = 2/7 x 3/2 - 1/7 = 3/7 - 1/7 = 2/7
15 tháng 5 2022
1.a,=(54+45+1).113
=100.113
=11300
b,=(3/7+8/14)+(4/9+10/18)
=1+1
=2
2.a,=13/10+1/3
=49/30
b,=12/9.(1/12+1/6)
=12/9.1/4
=1/3
c,=3/4.3/2
=9/8
d,=3/2-1/3
=7/6
VQ
15 tháng 5 2022
1:tính bằng cách thuận tiện nhất:
a)54 x 113 + 45 x 113 + 113
= 54 x 113 + 45 x 113 + 113x1
=113 x(54+45+1)
= 113x100
=1300
b)3/7 + 4/9 + 8/14 + 10/18
=(3/7+8/14)+(4/9+10/18)
= 1 + 1
=2
18 tháng 4 2023
(1-1/2)×(1-1/3)×(1-1/4)×(1-1/5)×1-1/6=1/2×2/3×3/4×4/5×5/6=1/6
LV
1
TT
4
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
5 tháng 5 2023
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6 : 1 : 2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6:2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 3
\(x\) = 3 : \(\dfrac{1}{4}\)
\(x\) = 12
NK
2
H
12 tháng 3 2023
`( 2/3 xx 4/5) xx 5/6`
`= 8/15 xx 5/6`
`= 40/90`
`=4/9`
__
`( 2/3 xx 4/5) xx 5/6`
`= 2/3 xx (4/5 xx 5/6)`
`= 2/3 xx 2/3`
`= 4/9`
-------
`(1/2 + 1/3) xx 1/5`
`= ( 3/6 +2/6) xx 1/5`
`= 5/6 xx1/5`
`= 5/30`
`=1/6`
__
`(1/2 + 1/3) xx 1/5`
`=1/2 xx 1/5 + 1/3 xx 1/5`
`= 1/10 + 1/15`
`=1/6`
NH
12 tháng 3 2023
a)
c1
`(2/3xx4/5)xx5/6`
`=8/15xx5/6`
`=4/9`
c2
`(2/3xx4/5)xx5/6`
`=2/3xx4/5xx5/6`
`=2/3xx5/6xx4/5`
`=5/9xx4/5`
`=4/9`
b)
c1
`(1/2+1/3)xx1/5`
`=(3/6+2/6)xx1/5`
`=5/6xx1/5`
`=1/6`
c2
`(1/2+1/3)xx1/5`
`=1/2xx1/5+1/3xx1/5`
`=1/10+1/15`
`=3/30+2/30`
`=5/30=1/6`
ND
Nguyễn Đức Trí
VIP
11 tháng 7 2023
a) \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{256}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+...-\dfrac{1}{128}+\dfrac{1}{128}-\dfrac{1}{256}\)
\(=1-\dfrac{1}{256}\)
\(=\dfrac{255}{256}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{13.14}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}\)
\(=1-\dfrac{1}{14}\)
\(=\dfrac{13}{14}\)
c) \(\dfrac{3}{15.18}+\dfrac{3}{18.21}+\dfrac{3}{21.24}+...+\dfrac{3}{87.90}\)
\(=3.\left(\dfrac{1}{15.18}+\dfrac{1}{18.21}+\dfrac{1}{21.24}+...+\dfrac{1}{87.90}\right)\)
\(=3.\left[\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}\right)+\dfrac{1}{3}.\left(\dfrac{1}{18}-\dfrac{1}{21}\right)+\dfrac{1}{3}.\left(\dfrac{1}{21}-\dfrac{1}{24}\right)+...+\dfrac{1}{3}.\left(\dfrac{1}{87}-\dfrac{1}{90}\right)\right]\)
\(=3.\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{24}+...+\dfrac{1}{87}-\dfrac{1}{90}\right)\)
\(=\dfrac{1}{15}-\dfrac{1}{90}\)
\(=\dfrac{6}{90}-\dfrac{1}{90}\)
\(=\dfrac{5}{90}=\dfrac{1}{18}\)
25 tháng 4 2022
1) 1/3 x 1/2 x 3/7 = 3/42 = 1/14
2) 5/4 x 1/3 +1/7 = 5/12 + 1/7 = 35/84 + 12/84 = 47/84
3) 8 x ( 8/9 - 2/3 ) = 8 x 2/9 = 16/9
4) 5/6 x 48/20 x 1/2 = 240/240 = 1
5) ( 2/5 + 3/4 ) + 8 = 23/20 + 8 = 23//20 + 160/20 = 183/20
6) 10 x ( 1/2 - 1/5 ) = 10 x 3/10 = 10/1 x 3/10 = 30/10 = 3
TN
3
17 tháng 4 2022
\(\dfrac{9}{10}\)
\(\dfrac{1}{24}\)
\(\dfrac{5}{2}\)
TL:
\(\frac{2}{3}\times\frac{1}{2}=\frac{2\times1}{3\times2}=\frac{2}{6}=\frac{1}{3}\)
HT
TL:
\(\frac{2}{3}\)x\(\frac{1}{2}\)= \(\frac{2}{6}\)
HT.