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Từ đầu bài ta có: y x 4 + y x 6 - y x 2 = 120
y x (4 + 6 - 2) = 120
y x 8 = 120
y = 120 : 8
Vậy y = 15
y : 8 × 32 + y : 3 × 18 - y : 5 × 10 = 120
y × 4 + y × 6 - y × 2 = 120
y × ( 4 + 6 - 2) = 120
y × 8 = 120
y = 120 : 8
y = 15
Vậy y = 15
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c)\(\dfrac{3}{8}\times\dfrac{5}{8}+y=\dfrac{5}{4}\)
\(\dfrac{15}{64}+y=\dfrac{5}{4}\)
\(y=\dfrac{5}{4}-\dfrac{15}{64}\)
\(y=\dfrac{65}{64}\)
d, \(\dfrac{3}{8}+\dfrac{5}{8}\times y=\dfrac{5}{4}\)
\(\dfrac{5}{8}\times y=\dfrac{5}{4}-\dfrac{3}{8}\)
\(\dfrac{5}{8}\times y=\dfrac{7}{8}\)
\(y=\dfrac{7}{8}:\dfrac{5}{8}\)
\(y=\dfrac{7}{5}\)
a, 3/4 x y = 3/5 + 3/10
3/4 x y = 9/10
y = 9/10 : 3/4
y = 6/5
b, 3/5 : y = 3/4 - 2/5
3/5 : y = 7/20
y = 3/5 : 7/20
y = 12/7
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1)\(y\times7:5+4\times8=134\)
\(\Leftrightarrow y\times7:5+32=134\)
\(\Leftrightarrow y\times7:5=102\)
\(\Leftrightarrow y\times7=510\)
\(\Leftrightarrow y=72,86\)
2) \(\dfrac{1}{4}:0,25-\dfrac{1}{8}:0,125+\dfrac{1}{2}:0,5-\dfrac{1}{10}\)
\(=0,25:0,25-0,125:0,125+0,5:0,5-\dfrac{1}{10}\)
\(=1-1+1-\dfrac{1}{10}\)
\(=\dfrac{9}{10}\)
\(y\times8+y+y=10\)
\(y\times8+y\times1+y\times1=10\)
\(y\times\left(8+1+1\right)=10\)
\(y\times10=10\)
\(y=10:10\)
\(y=1\)
y × 8 + y + y = 10
y × 8 + y × 1 + y × 1 = 10
y × (8 + 1 + 1) = 10
y × 10 = 10
y = 10 : 10
y = 1