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12 tháng 7 2017

Ta có: \(\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right).\dfrac{1}{3}\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right).\dfrac{1}{3}\)

\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right).\dfrac{1}{3}\)

\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\left(2^{32}+1\right).\dfrac{1}{3}\)

\(=\left(2^{32}-1\right)\left(2^{32}+1\right).\dfrac{1}{3}=\left(2^{64}-1\right).\dfrac{1}{3}=\dfrac{2^{64}-1}{3}\)

Vậy ...

12 tháng 7 2017

ko có j haha _ Yuki _ Dễ thương _

23 tháng 8 2015

3  = 2^2 - 1 

Áp dụng HĐT a^2 - b^2 

kq : 2^128 - 1 

4 tháng 8 2016

[Toán 8] Rút gọn $ (3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)$ | HOCMAI Forum - Cộng đồng học sinh Việt Nam

14 tháng 1 2016

-x^61+5*x^60+x^59-5*x^58-x^55+5*x^54+x^53-5*x^52-x^49+5*x^48+x^47-5*x^46x^43+5*x^42+x^41-5*x^40-x^37+5*x^36+x^35-5*x^34-x^49+5*x^48+x^47-5*x^46x^43+5*x^42+x^41-5*x^40-x^37+5*x^36+x^35-5*x^34-x^31+5*x^30+x^27-5*x^26-x^25+5*x^24+x^21-5*x^20-x^19+5*x^18+x^15-5*x^14-x^13+5*x^12+x^9-5*x^8-x^7+5*x^6+x^3-5*x^2-x+5

8 tháng 4 2020

\(3(2^2+1)(2^4+1)(2^8+1)(2^16 +1) \)

\( = (2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)\)

\( = (2^4-1)(2^4+1)(2^8+1)(2^16+1) \)

\( = (2^8-1)(2^8+1)(2^16+1) \)

\(= (2^16 -1)(2^16+1) = 2^32 - 1\)

8 tháng 4 2020

3(2^2 +1) (2^4 +1 ) (2^8 +1) (2^16 +1)

= (4-1)(2^2+1)(2^4 +1)(2^8+1)(2^16+1)

= [(2^2-1)(2^2+1)] (2^4+1) (2^8+1)(2^16+1)

=(2^4 -1)(2^4+1)(2^8+1)(2^16+1)

=(2^8-1)(2^8+1)(2^16+1)

= (2^16-1)(2^16+1)

= 2^23 -1 

Chúc bạn học tốt

10 tháng 10 2019

câu a là hằng đẳng thức luôn

A=(2x+4)^2

B khai triển tung tóe ra thì phần sau triệt tiêu hết còn 4(a^2+b^2+c^2)

câu c cảm giác sai đề vì mấy câu này phải là (3x)^ ms ra hdt chứ nhỉ

18 tháng 12 2016

2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)

=(2^4-1)(2^4+1)(2^8+1)(2^16+1)

=(2^8-1)(2^8+1)(2^16+1)

=(2^16-1)(2^16+1)

=2^32-1

12 tháng 12 2017

2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1

chúc bn hok tốt @_@

19 tháng 6 2019

\(b,\)\(B=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=1.\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2^{16}-1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=\left(2^{32}-1\right)\left(2^{32}+1\right)-2^{64}\)

\(\Rightarrow B=2^{64}-1-2^{64}=-1\)

19 tháng 6 2019

a) Đặt \(A=\left(\frac{1}{2}+1\right).\left(\frac{1}{4}+1\right).\left(\frac{1}{16}+1\right)...\left(1+\frac{1}{2^{2n}}\right)\)

Rút gọn:  \(A=\frac{2+1}{2}.\frac{4+1}{4}.\frac{16+1}{16}...\frac{2^{2.n}+1}{2^{2.n}}=\frac{2^{2.0}+1}{2^{2.0}}.\frac{2^{2.1}+1}{2^{2.1}}.\frac{2^{2.2}+1}{2^{2.2}}...\frac{2^{2.n}+1}{2^{2.n}}\)

\(\Rightarrow A=\frac{\left(2^{2.0}+1\right).\left(2^{2.1}+1\right).\left(2^{2.2}+1\right)...\left(2^{2.n}+1\right)}{2^{2.0}.2^{2.1}.2^{2.2}...2^{2.n}}.\)

b) Đặt \(B=\left(2+1\right).\left(2^2+1\right).\left(2^4+1\right).\left(2^8+1\right).\left(2^{16}+1\right).\left(2^{32}+1\right)-2^{64}\)

\(\Leftrightarrow B=\left(2-1\right).\left(2+1\right).\left(2^2+1\right)...\left(2^{32}+1\right)-2^{64}=\left(2^2-1\right).\left(2^2+1\right)...\left(2^{32}+1\right)-2^{64}\)

\(\Leftrightarrow B=\left(2^4-1\right).\left(2^4+1\right).\left(2^8+1\right)...\left(2^{32}+1\right)-2^{64}=\left(2^8-1\right).\left(2^8+1\right)...\left(2^{32}+1\right)-2^{64}\)

\(\Leftrightarrow B=\left(2^{16}-1\right).\left(2^{16}+1\right).\left(2^{32}+1\right)-2^{64}=\left(2^{32}-1\right).\left(2^{32}+1\right)-2^{64}\)

\(\Leftrightarrow B=2^{64}-1-2^{64}=-1\)Vậy B =-1.

1 tháng 12 2017

a)  (6x + 1)2 + (6x - 1)2 - 2(1 + 6x)(6x - 1) 

= (6x + 1 - 6x + 1)2 = 4

b) 3(22 + 1)(24 + 1)(28 + 1)(216 +1)

= (22 - 1)(22 + 1)(24 + 1)(28 + 1)(216 + 1)

= (24 - 1)(24 + 1)(28 + 1)(216 + 1) 

= (28 - 1)(28 + 1)(216 + 1)

= (216 - 1)(216 + 1) = 232 - 1

31 tháng 12 2019

mk ko ghi lại đề 

= (4-1)(.......

=(2^2-1)(2^2+1)(.....

=(2^4-1)(2^4+1)(......

=....

=2^32-1

\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

                                                                                      \(=\left(x^4-1\right)\left(x^4+1\right)\left(x^8+1\right)\left(x^{16}+1\right)\)

                                                                                   \(=\left(x^8-1\right)\left(x^8+1\right)\left(x^{16}+1\right)\)

                                                                                   \(=\left(x^{16}-1\right)\left(x^{16}+1\right)\)

                                                                                  \(=x^{32}-1\)