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nhiều thế ren giải được ma bik giải xng rồi có dc chi hông?
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\(\dfrac{11}{12}x\dfrac{6}{9}-\dfrac{3}{8}=\dfrac{66}{108}-\dfrac{3}{8}=\dfrac{17}{72}\)
\(\dfrac{5}{7}:\dfrac{9}{14}-\dfrac{17}{18}=\dfrac{70}{63}-\dfrac{17}{18}=\dfrac{1}{6}\)
\(\dfrac{11}{12}\) x \(\dfrac{6}{9}-\dfrac{3}{8}=\dfrac{11}{18}-\dfrac{3}{8}=\dfrac{88}{144}-\dfrac{54}{144}=\dfrac{34}{144}=\dfrac{17}{72}\)
\(\dfrac{5}{7}:\dfrac{9}{14}-\dfrac{17}{18}\)\(=\dfrac{5}{7}\) x \(\dfrac{14}{9}-\dfrac{17}{18}=\dfrac{10}{9}-\dfrac{17}{18}=\dfrac{20}{18}-\dfrac{17}{18}=\dfrac{3}{18}=\dfrac{1}{6}\)
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a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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a) 5/11 + 4/7 + 6/11 + 10/7 = (5/11 + 6/11) + (4/7 + 10/7)
= 1 + 2 = 3
b) 15/9 + 5/8 - 5/9 + 11/8 = (15/9 - 5/9) + (5/8 + 11/8)
= 10/9 + 2 = 28/9
c) 21/12 + 4/11 + 7/11 - 11/12 = (21/12 - 11/12) + (4/11 + 7/11)
= 10/12 + 1 = 11/6
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1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
=(1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+20+10
=20+20+20+20+20+20+20+20+20+20+10
=20×10+10
=200+10
=210
= ( 1 + 19 ) + ( 2 + 18 ) + ( 3 + 17 ) + (4 + 16 ) + ( 5 + 15 ) + ( 6 + 14 ) + ( 7 + 13 ) + ( 8 + 12) + ( 9+ 11 ) + 20
= 20 + 20 + 20 +20 + 20 +20 + 20 + 20 + 20 +20
= 20 x 10
= 200
tui đầu tiên đó
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a) 4/7 + 9/11
= 44/77 + 63/ 77
= 107/77
b) 11/12 * 6/9 - 3/8
= 66/108 - 3/8
= 11/18 - 3/8
= 44/72 - 27/72
= 17/72
c) 5/7 : 9/14 -17/18
= 5/7 * 14/9 - 17/18
= 70/63 - 17/18
= 10/9 - 17/18
= 20/18 - 17/18
= 3/18
= 1/6
OK
a, \(\frac{7}{5}+\frac{9}{7}+\frac{6}{5}+\frac{11}{7}\)
C1: \(\frac{94}{35}+\frac{6}{5}+\frac{11}{7}=\frac{136}{35}+\frac{11}{7}=5\frac{16}{35}\)
C2: \(=\left(\frac{7}{5}+\frac{6}{5}\right)+\left(\frac{9}{7}+\frac{11}{7}\right)=\frac{13}{5}+\frac{20}{7}=5\frac{16}{35}\)
b,
C1 : \(\frac{8}{14}+\frac{2}{11}+\frac{12}{14}+\frac{31}{11}=\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\frac{58}{77}+\frac{6}{7}+\frac{31}{11}=\frac{124}{77}+\frac{31}{11}=4\frac{3}{7}\)
C2:
\(\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\left(\frac{4}{7}+\frac{6}{7}\right)+\left(\frac{2}{11}+\frac{31}{11}\right)=\frac{10}{7}+3=3\frac{10}{7}=4\frac{3}{7}\)
**** cko t nha , xin xin đó
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