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Câu a: \(\frac{54}{63}\) và \(\frac{28}{63}\)
Câu b: \(\frac{55}{88}\)và \(\frac{24}{88}\)
a) \(\frac{6}{7}=\frac{6.9}{7.9}=\frac{54}{63}\)
\(\frac{4}{9}=\frac{4.7}{9.7}=\frac{28}{63}\)
b) \(\frac{5}{8}=\frac{5.11}{8.11}=\frac{55}{88}\)
\(\frac{3}{11}=\frac{3.8}{11.8}=\frac{24}{88}\)
c) \(\frac{6}{7}=\frac{6.3}{3.7}=\frac{18}{21}\)
\(\frac{5}{21}=\frac{5}{21}\)
d) \(\frac{7}{21}=\frac{7.4}{21.4}=\frac{28}{84}\)
\(a,\),\(\frac{6}{7}\)và \(\frac{4}{9}\)
Ta có: \(\frac{6}{7}=\frac{6\times9}{7\times9}=\frac{54}{63}\) \(;\) \(\frac{4}{9}=\frac{4\times7}{9\times7}=\frac{28}{63}\)
\(b,\)\(\frac{5}{8}\)và \(\frac{3}{11}\)
Ta có: \(\frac{5}{8}=\frac{5\times11}{8\times11}=\frac{55}{88}\) \(;\) \(\frac{3}{11}=\frac{3\times8}{11\times8}=\frac{24}{88}\)
\(c,\)\(\frac{6}{7}\)và \(\frac{5}{21}\)
Ta có: \(\frac{6}{7}=\frac{6\times3}{7\times3}=\frac{18}{21}\) \(;\)\(\frac{5}{21}\)
\(d,\)\(\frac{7}{21}\)và \(\frac{23}{84}\)
Ta có: \(\frac{7}{21}=\frac{7\times4}{21\times4}=\frac{28}{84}\)\(;\)\(\frac{23}{84}\)
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(6:3/5-7/6×6/7) : (21/5×10/11+57/11)
=(10-1):(42/11+57/11)
=9:9
=1
(6:3/5-7/6x6/7):(21/5x10/11+57/11)
= (10-1):(42/11+57/11)
=9:9
=1
~~~~ Hoc tot ~~~~~
a) 3/2 x 4/7 = 6/7
8/21 : 2/3= 4/7
8/21 : 4/7 = 2/3
4/7 x 2/3 = 8/21
b) 3/11 x 2 = 6/11
6/11: 3/11 = 2
125/90=25/18
84/91=12/13
75/45=25/15=5/3
6/7=18/21=54/63=104/126
`3/7 + 4/5 + 4/7`
`= (3/7 +4/7)+4/5`
`= 7/7 +4/5`
`= 1 + 4/5`
`= 5/5 +4/5`
`=9/5`
`------`
`6/11 + 2/15 + 5/11`
`=(6/11 + 5/11)+2/15`
`= 1 + 2/15`
`= 15/15 +2/15`
`= 17/15`
`-----`
`4/9 + 2/5 + 15/27`
`= (4/9 + 15/27 )+2/5`
`= 1+2/5`
`=5/5 +2/5`
`=7/5`
`-----`
`6/13 + 9/32 + 21/26`
`= (6/13 + 21/26)+9/32`
`= ( 12/26 + 21/26)+9/32`
`= 33/26 +9/32`
`=645/416`
[6: 3/5 - 7/6 x 6/7] : [ 21/5 x 10/11 + 57/11]
= 9 : 9
= 1
\(\left(6:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}\right):\left(\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}\right)\)
\(=\left(10-1\right):\left(\frac{42}{11}+\frac{57}{11}\right)\)
\(=9:9\)
\(=1\)
84/21 - (7/6 + 11/7)
= 84/21 - (49/42 + 66/42)
= 84/21 - 115/42
= 168/42 - 115/42
= 53/42