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IM
12 tháng 9 2016
14)
\(\left(27.45+27.55\right):\left(2+4+6+...+18\right)\)
\(=\left[27\left(45+55\right)\right]:\left[\frac{\left(18+2\right)9}{2}\right]\)
\(=\left(27.100\right):90\)
\(=2700:90\)
\(=30\)
15)
\(\left(26.180-26.12\right):\left(32-18+....+8-4\right)\)
\(=26\left(180-12\right):\left(14+4+4+4+4+4+4+4\right)\)
\(=26.168:42\)
\(=84\)
KL
24 tháng 8 2017
15 - (-15 + 2) = 15 + 13 = 28
(-14) - (17 - 8) = -14 - 9 = -23
15 - (21- 7) = 15 - 14 = 1
34 + (-15) - 17 = 19 - 17 = 2
(-34) + (-12) + 18 = -46 + 18 = -28
27 - 15 - 19 = 12 - 19 = -7
34 - (-15) + 8 = 49 + 8 = 57
-37 + 13 - 25 = -24 - 25 = -49
40 - 17 + (-25) = 23 + (-25) = -2
16 + (-15) - 18 = 1 - 18 = -17
15 - 14 - 13 = 1 - 13 = -12
-27 + 15 - 17 = -12 - 17 = -29
34 - 71 = -37
28 - 125 = -97
13 + (-27) = -14
14 - (-34) = 48
28 - (-16) = 44
-15 - 8 = -23
-27 - 34 = -61
-25 - (-18) = -7
46 - 25 - (-25) = 21 + 25 = 46
-37 - (-24) = -13
46 - (-15) = 61
-26 - 6 + 7 = -32 + 7 = -25
@linhcute
CN
1
AH
Akai Haruma
Giáo viên
20 tháng 2 2022
Lời giải:
a.
$\frac{6}{13}+\frac{-15}{39}=\frac{6}{13}+\frac{-5}{13}=\frac{6+(-5)}{13}=\frac{1}{13}$
b.
$\frac{-8}{18}+\frac{-15}{27}=\frac{-4}{9}+\frac{-5}{9}=\frac{-4-5}{9}=\frac{-9}{9}=-1$
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
1 tháng 1 2018
a, => x-12-15=x-19
=> x-27=x-19
=> x-x=-19+27
=> 0x=8
=> ko tốn tại x tm
b, => x-18+x=x-8
=> 2x-18=x-8
=> 2x-x=-8+18
=> x=10
k mk nha
PA
0
S
1 tháng 2
câu 1)
\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2)
\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)
\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4)
\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5)
\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6)
\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7)
\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8)
\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9)
\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10)
\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11)
\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12)
\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13)
\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14)
\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15)
\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16)
\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)
LV
2
\(\dfrac{-8}{18}+\dfrac{-15}{27}\\ =\dfrac{-4}{9}+\dfrac{-5}{9}\\ =\dfrac{-4+\left(-5\right)}{9}\\ =\dfrac{-9}{9}\\ =-1\)