![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
44 + 7 . x = 103 : 10
44 + 7 . x = 100
7 . x = 100 - 44
7 . x = 56
x = 56 : 7
x = 8
Vậy x bằng 8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\cdot\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{1}{10}\right)=-\dfrac{7}{4}\\ \Leftrightarrow-8x=-\dfrac{15}{4}\\ \Leftrightarrow x=\dfrac{15}{32}\)
\(4\left(\dfrac{3}{4}+x\right)-\dfrac{1}{5}=7x-\dfrac{1}{7}\\ \Leftrightarrow3x=\dfrac{103}{35}\\ \Leftrightarrow x=\dfrac{103}{105}\)
\(3\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{1}{10}\right)=-\dfrac{7}{4}\)
\(\Rightarrow\dfrac{3}{2}-3x-5x+\dfrac{1}{2}=-\dfrac{7}{4}\)
\(\Rightarrow2-8x=-\dfrac{7}{4}\)
\(\Rightarrow8x=2+\dfrac{7}{4}\)
\(\Rightarrow8x=\dfrac{15}{4}\)
\(\Rightarrow x=\dfrac{15}{32}\)
___________
\(4\left(\dfrac{3}{4}+x\right)-\dfrac{1}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow3+4x-\dfrac{1}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow4x+\dfrac{14}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow7x-4x=\dfrac{14}{5}+\dfrac{1}{7}\)
\(\Rightarrow3x=\dfrac{103}{35}\)
\(\Rightarrow x=\dfrac{103}{105}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(27^{15}=\left(3^3\right)^{15}=3^{45}\)
\(81^{11}=\left(3^4\right)^{11}=3^{44}\)
vì 344 < 345 nên 8111 < 2715
![](https://rs.olm.vn/images/avt/0.png?1311)
Cái dề, bài này giúp á, tính ra là ok mà
(13/10x - 15).(-5/14) = 3
13/10x - 15 = 3 : (-5/14)
13/10x - 15 = 3 x (-14/5)
13/10x - 15 = -42/5
=> 13/10x = -42/5 + 15
=> 13/10x = 33/5
=> x = 33/5 : 13/10
=> x = 33/5 x 10/13
=> x = 66/13
bn tự lm típ, tính ra là ok mà
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10}{3}.x+\frac{67}{4}=\frac{53}{4}\)
\(\frac{10}{3}.x=\frac{53}{4}-\frac{67}{4}\)
\(\frac{10}{3}.x=-\frac{7}{2}\)
\(x=-\frac{7}{2}:\frac{10}{3}\)
\(x=-\frac{21}{20}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1: =-2/9(15/17+2/17)=-2/9
2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)
=-2-7/30=-67/30
3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
1: =-2/9(15/17+2/17)=-2/9
2: =−63+−2190=−63+−2190
=-2-7/30=-67/30
3: =34⋅75+97⋅32=34⋅75+97⋅32
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 17.81+19.17-150=17(81+19)-150
=17.100-150
=1700-150=1550
b) 20-[50-(5-1)2 ]=20-[50-42 ]
=20-[50-16]
=20-34=-14
c) 44+7x=103:10
44+7x=102
44+7x=100
7x=100-44
7x=56
x=56:7
x=8
Vậy x=8.
d) |x-1|+3=5
|x-1|=5-3
|x-1|=2
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
Vậy x\(\in\){-1;3}
Vì a\(⋮\)9 nên a\(\in\)B(9)={0;9;18;27;36;...}
![](https://rs.olm.vn/images/avt/0.png?1311)
44+7.x=10^3:10
44+7.x=1000:10
44+7.x=100
7x=100-44
7x=56
x=56:7
x=8
vậy x=8