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ND
3
VT
6 tháng 3 2023
\(a,\dfrac{9}{17}+\dfrac{15}{4}=\dfrac{36}{68}+\dfrac{255}{68}=\dfrac{291}{68}\\ b,\dfrac{19}{121}-\dfrac{1}{11}=\dfrac{19}{121}-\dfrac{11}{121}=\dfrac{8}{121}\\ c,\dfrac{4}{15}+3=\dfrac{4}{15}+\dfrac{45}{15}=\dfrac{49}{15}\\ d,3-\dfrac{5}{9}=\dfrac{27}{9}-\dfrac{5}{9}=\dfrac{22}{9}\)
NK
6 tháng 3 2023
\(a,\dfrac{9}{17}+\dfrac{15}{4}=\dfrac{36}{68}+\dfrac{255}{68}=\dfrac{291}{68}\)
\(b,\dfrac{19}{121}-\dfrac{1}{11}=\dfrac{19}{121}-\dfrac{11}{121}=\dfrac{8}{121}\)
\(c,\dfrac{4}{15}+3=\dfrac{4}{15}+\dfrac{3}{1}=\dfrac{4}{15}+\dfrac{45}{15}=\dfrac{49}{15}\)
\(d,3-\dfrac{5}{9}=\dfrac{3}{1}-\dfrac{5}{9}=\dfrac{27}{9}-\dfrac{5}{9}=\dfrac{22}{9}\)
HT
1
15 tháng 2 2023
\(\dfrac{3}{9}+\dfrac{9}{15}+\dfrac{16}{24}=\dfrac{1}{3}+\dfrac{9}{15}+\dfrac{2}{3}=\dfrac{5}{15}+\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{24}{15}=\dfrac{8}{5}\)
\(\dfrac{4}{10}+\dfrac{12}{32}+\dfrac{9}{15}=\dfrac{2}{5}+\dfrac{3}{8}+\dfrac{3}{5}=\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{3}{8}=\dfrac{5}{5}+\dfrac{3}{8}=1+\dfrac{3}{8}=1\dfrac{3}{8}=\dfrac{11}{8}\)
\(\dfrac{1}{6}+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{18}=\dfrac{3}{18}+\dfrac{9}{18}+\dfrac{6}{18}+\dfrac{1}{18}=\dfrac{19}{18}\)
H
3 tháng 3 2023
`4/7+4`
`=4/7+4/1`
`=4/7+28/7`
`=32/7`
__
`3+6/11`
`=33/11+6/11`
`=39/11`
__
`3-5/7`
`=3/1-5/7`
`=21/7-5/7`
`=16/7`
__
`21/9-2`
`=21/9-18/9`
`=3/9`
`=1/3`
__
`15/24+2`
`=15/24+48/24`
`=63/24`
`=21/16`
__
`63/45-20/25`
`=63/45-4/5`
`=63/45-36/45`
`=27/45`
`=9/15`
__
`3/4-2/8`
`=3/4-1/4`
`=2/4`
__
`6/7-5/8`
`=48/56-35/56`
`=13/56`
__
`37/45-5/9`
`=37/45-25/45`
`=12/45`
`=4/15`
__
`46/39-11/13`
`=46/39-33/39`
`=13/39`
`=1/2`
__
`5/12+3/4+1/3`
`=5/12+9/12+4/12`
`=14/12+4/12`
`=18/12`
`=3/2`
__
`1/2+3/7+11/14`
`=7/14+6/14+11/14`
`=13/14+11/14`
`=24/14`
`=12/7`
__
`7/10-(1/5+1/4)`
`=7/10-(4/20+5/20)`
`=7/10-9/20`
`=14/20-9/20`
`=5/20`
`=1/4`
__
`15/4-2/3-3/4`
`=(15/4-3/4)-2/3`
`=12/4-2/3`
`=3-2/3`
`=9/3-2/3`
`=7/3`
C
19 tháng 3 2023
`1)1/2:2/3 .... 2/3 : 1/2`
`=>1/2xx3/2 .... 2/3xx2`
`=>3/4 .... 4/3`
Vì `3/4 < 1` và `4/3>1`
`=>3/4<4/3`
__
`4/7:2/5 ... 4/7 : 3/5`
`=>4/7xx5/2....4/7xx5/3`
`=>20/14...20/21`
`=>10/7...20/21`
Vì `10/7>1` và `20/21<1`
`=>10/7>20/21`
__
`4/15:4/7....2/5xx10/3`
`=>4/15xx7/4...20/15`
`=>7/15...20/15`
Vì `7<20` nên `7/15<20/15`
__
`5/6...15/18-11/18`
`=>5/6...4/18`
Ta có : MSC : `18`
`5/6 = 15/18`
Vì `15>4` nên `5/6 > 4/18`
21 tháng 2 2022
Tính:
2/7 + 5/7=1
8/15 + 6/15 =14/15
2/9 + 3/9 + 4/9=9/9=1
[ Không cần làm phép tính ]Điền vào ô trống <,>,= :
3/5 + 1/5 = 1/5 + 3/5
7/9 + 1/9 < 7/9 + 1/9 + 1/9
3/7 + 2/7 < 3/7 + 4/7
1/5 + 3/5 < 2/5 + 3/5
21 tháng 2 2022
Tính:
2/7 + 5/7=1
8/15 + 6/15 =14/15
2/9 + 3/9 + 4/9=9/9=1
[ Không cần làm phép tính ]Điền vào ô trống <,>,= :
3/5 + 1/5 = 1/5 + 3/5
7/9 + 1/9 < 7/9 + 1/9 + 1/9
3/7 + 2/7 < 3/7 + 4/7
1/5 + 3/5 < 2/5 + 3/5
2 tháng 7 2021
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 4 2023
( \(\dfrac{2}{15}\) - \(\dfrac{1}{20}\) + \(\dfrac{3}{15}\) - \(\dfrac{9}{28}\) + \(\dfrac{2}{3}\)) : \(\dfrac{3}{4}\)
= { (\(\dfrac{2}{15}\) + \(\dfrac{3}{15}\)) + \(\dfrac{2}{3}\) - (\(\dfrac{1}{20}\) + \(\dfrac{9}{28}\))} : \(\dfrac{3}{4}\)
= { \(\dfrac{1}{3}\) + \(\dfrac{2}{3}\) - \(\dfrac{13}{35}\)) : \(\dfrac{3}{4}\)
= ( 1 - \(\dfrac{13}{35}\)): \(\dfrac{3}{4}\)
= \(\dfrac{22}{35}\) : \(\dfrac{3}{4}\)
= \(\dfrac{88}{105}\)
1 tháng 5 2016
\(\frac{4}{9}x\frac{7}{5}\)=\(\frac{28}{45}\)
\(\frac{15}{7}:9\)=\(\frac{5}{21}\)
\(\frac{2}{5}x\frac{3}{4}-\frac{1}{8}\) \(\frac{3}{10}-\frac{1}{8}\)=\(\frac{7}{40}\)
\(\frac{4}{3}+\frac{1}{3}-\frac{1}{5}\)= \(\frac{5}{3}-\frac{1}{5}\)=\(\frac{22}{15}\)
16 tháng 3 2020
Làm 1 câu
10/3...>...1/3
Mấy câu ssu tự quy đồng hay gì gì đấy!
KV
29 tháng 4 2022
4/15 + 1/2
= 8/30 + 15/30
= 23/30
51/9 - 2/3
= 51/9 - 6/9
= 45/9
= 5
3/4 × 15/26
= 45/104
7/3 : 5/14
= 7/3 × 14/5
= 98/15
\(\frac{4}{15}\)\(\div\)\(\frac{1}{3}\)\(+\)\(\frac{1}{15}\)\(\div\)\(\frac{1}{3}\)\(+\)\(\frac{4}{9}\)
\(=\)\(\frac{4}{15}\)\(\times\)\(3\)\(+\)\(\frac{1}{15}\)\(\times\)\(3\)\(+\)\(\frac{4}{9}\)
\(=\)\(3\)\(\times\)\(\left(\frac{4}{15}+\frac{1}{15}\right)\)\(+\)\(\frac{4}{9}\)
\(=\)\(3\)\(\times\)\(\frac{5}{15}\)\(+\)\(\frac{4}{9}\)
\(=\)\(3\)\(\times\)\(\frac{1}{3}\)\(+\)\(\frac{4}{9}\)
\(=\)\(1\)\(+\)\(\frac{4}{9}\)
\(=\)\(\frac{13}{9}\)
\(\frac{4}{15}\div\frac{1}{3}+\frac{1}{15}\div\frac{1}{3}+\frac{4}{9}\)
\(=\left(\frac{4}{15}+\frac{1}{15}\right)\times3+\frac{4}{9}\)
\(=\frac{1}{3}\times3+\frac{4}{9}\)
\(=1+\frac{4}{9}=\frac{13}{9}\)