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a) Ta có: \(4\left(x-2\right)-2\left(x+3\right)=-28\)
\(\Leftrightarrow4x-8-2x-6+28=0\)
\(\Leftrightarrow2x+14=0\)
\(\Leftrightarrow2x=-14\)
hay x=-7
Vậy: x=-7
b) Ta có: \(3x+7-9x=-11\)
\(\Leftrightarrow-6x+7+11=0\)
\(\Leftrightarrow-6x+18=0\)
\(\Leftrightarrow-6x=-18\)
hay x=3
Vậy: x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
/x-3/=7-(-2)
/x-3/=9
x=/9+3/
x=/12/
x=/12/
<=> x= 12; -12
( 3x-24)*73=2*74
(3x-16)*343=4802
3x-16=14
3x=14+16
3x=30
=> x = 10
x-[42+(-28)]=-8
x-14=8
x=8+14
x=22
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow2\left(4-3x\right)=10+4\)
\(\Leftrightarrow2\left(4-3x\right)=14\)
\(\Leftrightarrow4-3x=7\)
\(\Leftrightarrow3x=-3\)
\(\Leftrightarrow x=-1\)
b.
\(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow3\left(-x+7\right)=-18+12=-6\)
\(\Leftrightarrow-x+7=-6:3=-2\)
\(\Leftrightarrow x=9\)
c.
\(-45:5.\left(-3-2x\right)=3\)
\(\Leftrightarrow-9.\left(-3-2x\right)=3\)
\(\Leftrightarrow-3-2x=-\dfrac{1}{3}\)
\(\Leftrightarrow2x=-\dfrac{8}{3}\)
\(\Leftrightarrow x=-\dfrac{4}{3}\notin Z\left(loại\right)\)
Câu này em ghi sai đề?
d.
\(3x-28=x+36\)
\(\Leftrightarrow2x=28+36\)
\(\Leftrightarrow2x=64\)
\(\Leftrightarrow x=32\)
e.
\(\left(-12\right)^2.x=56+10.13x\)
\(\Leftrightarrow144x=56+130x\)
\(\Leftrightarrow144x-130x=56\)
\(\Leftrightarrow14x=56\)
\(\Leftrightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(10,\Rightarrow x-14=-8\Rightarrow x=6\\ 11,\Rightarrow7-x-32=-25\\ \Rightarrow-25-x=-25\Rightarrow x=0\\ 12,\Rightarrow3x-16=\dfrac{2\cdot7^4}{7^3}=2\cdot7=14\\ \Rightarrow3x=30\Rightarrow x=10\\ 13,\Rightarrow\left[{}\begin{matrix}x-4=5\\x-4=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=9\\x=-1\end{matrix}\right.\\ 14,\Rightarrow\left(2x+11\right)^2=2^4:2^4=1\\ \Rightarrow\left[{}\begin{matrix}2x+11=1\\2x+11=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=-6\end{matrix}\right.\\ 15,\Rightarrow7^{3x-2}=7^3\cdot4+7^3\cdot3=7^3\cdot7=7^4\\ \Rightarrow3x-2=4\\ \Rightarrow3x=6\Rightarrow x=2\)
10) x - [42 + (-28)] = -8
x - 14 = -8
x = -8 + 14 = 6
11) (7-x) - (25 +7) = -25
(7 -x) - 32 = -25
7 -x = -25 + 32 = 7
x = 7 -7 = 0
12) (3x - 24) . 73 = 2 . 74
(3x - 16) . 343 = 4802
3x - 16 = 4802 : 343= 14
3x = 14 + 16 = 30
x = 30 : 3 =10
13) (x - 4)2 = 25
⇒ 52 = 25
⇒ x - 4 = 5
⇒ x = 5 + 4 =9
14) 24(2x + 11)2 = 42
16(2x + 11)2 = 16
(2x + 11)2 = 16 : 16 = 1
⇒ 2x + 11 = 1
⇒ 2x = 11 + 1 = 12
⇒ x = 12 : 2 = 6
15) 73x-2 - 3.73 = 73 . 4
73x-2 - 1029 = 1372
73x-2 = 1372 + 1029 = 2401
⇒ 74 = 2401
⇒ 3x - 2 = 4
⇒ 3x = 4 + 2 = 6
⇒ x = 6 : 3 =2
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3x-18.28:14=308\)
\(=>3x-36=308\)
\(=>3x=344\)\(\)
\(=>x=\frac{344}{3}\)
\(\)b)\(38+\left|x\right|=\left(-12\right)+65\)
\(=>38+\left|x\right|=53=>\left|x\right|=15=>\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
c)\(15+3.\left(x-1\right):5=30\)
\(=>15+3.\left(x-1\right)=150\)
\(=>3.\left(x-1\right)=135\)
\(x-1=45=>x=46\)
d) \(5.\left(7-3x\right)+7.\left(2+2x\right)=1\)
\(=>35-15x+14+14x=1\)
\(=>49-x=1=>x=48\)
e)\(3.\left(x-7\right)=21\)
\(=>x-7=7=>x=14\)
g)\(\left[\left(6x-72\right):2-84\right]:28=5628\)
\(\left(6x-72\right):2-84=157584\)
\(\left(6x-72\right):2=157668\)
\(6x-72=315336\)
\(6x=315408=>x=52568\)
h)\(123-5\left(x+4\right)=28\)
\(5.\left(x+4\right)=95\)
\(x+4=19=>x=15\)
p)\(14.\left(x-3\right)-138=73\)
\(14.\left(x-3\right)=211\)
\(x-3=\frac{211}{14}=>x=\frac{253}{14}\)
\(t\)
\(\left|x\right|-5=2\)
\(\left|x\right|=7=>\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
v)\(4x-72=\left|100-8.25\right|\)
\(4x-72=\left|-100\right|\)
\(4x-72=100=>4x=172=>x=43\)
cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt ^^
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bn đừng nói ai xin lỗi với mình nữa nhé ! trả lời nick mình rồi mình sẽ nói cho
![](https://rs.olm.vn/images/avt/0.png?1311)
`4(3x-2)-2x=28`
`12x-8-2x=28`
`12x-2x=28+8`
`(12-2)x=36`
`10x=36`
`x=36:10=18/5`
`4(3x-2)-2x=28`
`12x-8-2x=28`
`12x-2x=28+8`
`(12-2)x=36`
`10x=36`
`x=36:10`
`x=18/5`