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Ta có: \(3^{x+3}\cdot3^{2x-1}+3^{2x}\cdot3^{x+1}=324\)
\(\Leftrightarrow3^{3x+2}+3^{3x+1}=324\)
\(\Leftrightarrow3^{3x+1}\cdot\left(3+1\right)=324\)
\(\Leftrightarrow3^{3x+1}\cdot4=324\)
\(\Leftrightarrow3^{3x+1}=81\)
\(\Leftrightarrow3^{3x+1}=3^4\)
\(\Rightarrow3x+1=4\)
\(\Rightarrow x=1\)
32x+1+32x=324
=> 32x.(31+1)=324
=> 32x.4=324
=> 32x=81
=> 32x=34
=> 2x=4
=> x=2
\(3^{2x+1}+9^x=324\)
\(3^{2x}.3+3^{2x}=324\)
\(3^{2x}.\left(3+1\right)=324\)
\(3^{2x}.4=324\)
\(3^{2x}=81\)
\(3^{2x}=3^4\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
vậy \(x=2\)
32x+1 + 9x = 324
9x lớn nhất là 81 trong phép cộng trên
9x = 92 = 81
x = 2
1: =>x+1/2=0 hoặc 2/3-2x=0
=>x=-1/2 hoặc x=1/3
2: =>7/6x=5/2:3,75=2/3
=>x=2/3:7/6=2/3*6/7=12/21=4/7
3: =>2x-3=0 hoặc 6-2x=0
=>x=3 hoặc x=3/2
4: =>-5x-1-1/2x+1/3=3/2x-5/6
=>-11/2x-3/2x=-5/6-1/3+1
=>-7x=-1/6
=>x=1/42
Ta có: \(3^{x+3}\cdot3^{2x-1}+3^{2x}\cdot3^{x+1}=324\)
\(\Leftrightarrow3^{3x+2}+3^{3x+1}=324\)
\(\Leftrightarrow3^{3x+1}\cdot\left(3+1\right)=324\)
\(\Leftrightarrow3^{3x+1}\cdot4=324\)
\(\Leftrightarrow3^{3x+1}=81=3^4\)
\(\Rightarrow3x+1=4\)
\(\Leftrightarrow x=1\)
\(3^{x+3}\cdot3^{2x-1}+3^{2x}\cdot3^{x+1}=324\)
\(3^{x+3+2x-1}+3^{2x+x+1}=324\)
\(3^{3x+2}+3^{3x+1}=324\)
\(3^{3x+1}\cdot\left(3+1\right)=324\)
\(3^{3x+1}\cdot4=324\)
\(3^{3x+1}=324:4\)
\(3^{3x+1}=81\)
\(3^{3x+1}=3^4\)
\(\Rightarrow3x+1=4\)
\(3x=4-1\)
\(3x=3\)
\(x=3:3\)
\(x=1\)