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a: Ta có: \(-5+\left(-37\right)-45+151-37+151\)
\(=\left(-5-45\right)-\left(37+37\right)+2\cdot151\)
\(=-50-74+302\)
=178
b: Ta có: \(53-145-359-53+145-259\)
\(=\left(53-53\right)-\left(145-145\right)-\left(359+259\right)\)
\(=-618\)
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\(B=1\frac{6}{41}.\left(\frac{12+\frac{12}{19}+\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}+\frac{3}{37}-\frac{3}{53}}\right):\left(\frac{4+\frac{4}{19}+\frac{4}{37}-\frac{4}{53}}{5+\frac{5}{19}+\frac{5}{37}-\frac{5}{53}}\right).\frac{124242423}{237373735}\)
\(B=1\frac{6}{41}.\left[\frac{12\left(\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}{3\left(\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}\right]:\left[\frac{4\left(\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}{5\left(\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}\right].\frac{124242423}{237373735}\)
\(B=1\frac{6}{41}\left(\frac{12}{3}.\frac{5}{4}\right).\frac{124242423}{237373735}\)
\(B=1\frac{6}{41}.5.\frac{123}{235}\)
\(B=\frac{47.5.123}{41.235}=\frac{47.5.41.3}{41.5.47}=3\)
B=\(1\frac{6}{41}.\left(\frac{12+\frac{12}{19}+\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}+\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{19}+\frac{4}{37}-\frac{4}{53}}{5+\frac{5}{19}+\frac{5}{37}-\frac{5}{53}}\right).\frac{124242423}{237373735}\)
B=\(\frac{47}{41}.\left(\frac{12.\left(1+\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}{3.\left(1+\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}:\frac{4.\left(1+\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}{5.\left(1+\frac{1}{19}+\frac{1}{37}-\frac{1}{53}\right)}\right).\frac{123.1010101}{235.1010101}\)
B=\(\frac{47}{41}.\left(\frac{12}{3}:\frac{4}{5}\right).\frac{123}{235}=\frac{47}{41}.\left(\frac{12}{3}.\frac{5}{4}\right).\frac{123}{235}\)
B=\(\frac{47}{41}.\frac{15}{3}.\frac{123}{235}=\frac{47.5.3.41.3}{41.3.5.47}=3\)
Vậy B=3
Chúc bn học tốt
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\(a.\left(35-815\right)-\left(795-65\right)\\ =35-815-795+65\\ =\left(35+65\right)-\left(815+795\right)\\ =100-1610=-1510\)
Bài 2:
a: Ta có: \(\left(35-815\right)-\left(795-65\right)\)
\(=35-815-795+65\)
\(=100-1600\)
=-1500
b: Ta có: \(5-197-2015-2015\)
\(=-2010-2212\)
=-4222
c: Ta có: \(1259-1409-12+1259+1409\)
\(=2518-12\)
=2506
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37 . 75 + 37 . 45 + 63 . 67 + 63 . 53
= ( 75 + 45 ) . 37 + ( 67 + 53 ) . 63
= 120 . 37 + 120 . 63
= 120 . ( 37 + 63 )
= 120 . 100
= 12000
37.75+37.45+63.67+63.53
=37(75+45)+63(67+53)
=37.120+63.120
=(37+63)120
=100.120
=12000
tk nha phamthiminhtrang
`31x-37+9x=53`
`31x+9x=53+37`
`(31+9)x=90`
`40x=90`
`x=9/4`
`31x - 37 + 9x = 53`
`40x -37 =53`
`40x = 53 +37 = 90`
`x=90/40 =9/4`