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3.|x+1|-2=4
3.|x+1|=4+2
3.|x+1|=6
|x+1|=6:3
|x+1|=2
Trường hợp 1 x+1=2
x=2-1
x=1
trường hợp 2
x+1=-2
x=(-2)-1
x=-3
==> x thuộc {1; -3}
k mk nha chúc học tốt
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\(\left(2x+1\right)^2=49\\ \Rightarrow\left[{}\begin{matrix}2x+1=7\\2x+1=-7\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=6\\2x=-8\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
Vậy \(x\in\left\{3;-4\right\}\)
Ta có: \(\left(2x+1\right)^2=49\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+1=7\\2x+1=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-4\right\}\)
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Đề bài: Tìm x
\(3.2^{x+1}+\frac{1}{2}=\frac{49}{2}\)
\(3.2^{x+1}=\frac{49}{2}-\frac{1}{2}\)
\(3.2^{x+1}=24\)
\(2^{x+1}=24\div3\)
\(2^{x+1}=8\)
\(2^{x+1}=2^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
Vậy \(x=2.\)
\(3.2^{2x+1}+\frac{1}{2}=\frac{49}{2}\)
\(\Leftrightarrow3.2^{2x+1}=\frac{48}{2}\)
\(\Leftrightarrow2^{2x+1}=8\)
\(\Leftrightarrow2^{2x+1}=2^3\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2x2 -1 = 49
2x2 = 49 + 1
2x2 = 50
x2 = 50 : 2
x2 = 25
=> 52 = 25
=> x2 = 52
=> x = 5
Vậy x = 5
x2 = 52
:)
\(2x^2-1=49\)
\(\Rightarrow2x^2=50\)
\(\Rightarrow x^2=25\)
\(\Rightarrow x=\pm5\)
Vậy \(\Rightarrow x=\pm5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x^2-1=49\)
\(\Leftrightarrow2x^2=50\)
\(\Leftrightarrow x^2=25\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
Vậy x = 5 hoặc x = -5
Soc Tong
\(2x^2-1=49\)
<=>2x2=50
<=> x2=25
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`(2x+1)^2=49`
`=> 2x+1=7` hoặc `2x+1=-7`
`=> 2x=6` hoặc `2x=-8`
`=> x=3` hoặc `x=-4`
2x2 - 1 = 49
2x2 - 1 = 72
2x - 1 = 7
2x = 7 + 1
2x = 8
x = 8 : 2
x = 4
2x2-1=49
2x2=49+1
2x2=50
2x2=2.25
2x2=2.52
x=5