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Đặt A = 1×2 + 2×3 + 3×4 + ... + 20×21
3A = 1×2×3 + 2×3×(4-1) + 3×4×(5-2) + ... + 20×21×(22-19)
= 1×2×3 - 1×2×3 + 2×3×4 - 2×3×4 + 3×4×5 - ... - 19×20×21 + 20×21×22
= 20×21×22
A = 20×21×22 : 3
= 20×22×7
= 3080
a/\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
= \(\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{1-3}{1+5}=\frac{-2}{6}=-3\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{18.19}+\frac{1}{19.20}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\)
\(=1-\frac{1}{20}=\frac{19}{20}\)
Vậy\(A=\frac{19}{20}\)
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{17}+\dfrac{1}{11}\right)}=\dfrac{3}{13}\)
\(\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\)
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}\)
\(=\dfrac{3}{13}\)
a, N(x) =3x^4 - 2x + 2x^3
+
P(x) = 5x - 6x^3 -8
_______________________
N(x) + P(x) = 3x^4 + 3x - 4x^3 - 8
@Huyền
b, B(x) = -2x^3 . (x^3y -2x^2y^2 + 5xy^3
= -2xy^2 . x^3y + (-2xy^2 ) .2x^2y^2 + (-2xy^2) . 5xy^3
= -2x^4y^3 + (-4x^3y^4) +(-10x^2y^5)
@Huyền
\(M=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{13}{4}-\frac{13}{5}+\frac{13}{7}+\frac{13}{11}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}{13.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{3}{13}\)
a; A = (1.2 + 2.3 + 3.4+ ... + 19.20)(13 - 3).(13 - 4)...(13 - 20)
A =(1.2 + 2.3 + 3.4 + ... + 19.20).(13 - 3).(13 - 4)...(13 - 13)...(13 - 20)
A = (1.2 + 2.3 + 3.4 + ... + 19.20).(13 - 3).(13 - 4)...0...(13 - 20)
A = 0
a; A = (1.2 + 2.3 + 3.4+ ... + 19.20)(13 - 3).(13 - 4)...(13 - 20)
A =(1.2 + 2.3 + 3.4 + ... + 19.20).(13 - 3).(13 - 4)...(13 - 13)...(13 - 20)
A = (1.2 + 2.3 + 3.4 + ... + 19.20).(13 - 3).(13 - 4)...0...(13 - 20)
A = 0
Chúc bạn học tốt !!!!