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(13.3x-2-3x):2=162
<=>3x-2(13-32)=162.2
<=>3x-2.4=324
<=>3x-2=324:4
<=>3x-2=81=34
<=>x-2=4
<=>x=6
Vậy...
Ta có: \(\left(13.3^{x-2}-3^x\right)\div2=162\)
\(\Leftrightarrow13.3^{x-2}-3^{x-2+2}=162.2\)
\(\Leftrightarrow13.3^{x-2}-3^2.3^{x-2}=324\)
\(\Leftrightarrow\left(13-9\right).3^{x-2}=324\)
\(\Leftrightarrow4.3^{x-2}=324\)
\(\Leftrightarrow3^{x-2}=\dfrac{324}{4}=81=3^4\)
\(\Leftrightarrow3^{x-2}=3^4\Leftrightarrow x-2=4\Leftrightarrow x=6\)
Vậy \(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\left(13.3^{x-2}-3x\right):2=162\)
\(\Rightarrow3^{x-2}\left(13-3^2\right)=162.2\)
\(\Rightarrow3^{x-2}.4=324\)
\(\Rightarrow3^{x-2}=324:4\)
\(3^{x-2}=81\)
\(3^{x-2}=3^4\)
\(\Rightarrow x-2=4\)
\(x=4+2\)
\(x=6\)
Vậy \(x=6\) là giá trị cần tìm
~ Chúc bn học tốt ~
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mình giải ý c
5(x+27)=200
(x+27)=200:5
(x+27)=40
x=40-27
x=13
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3ˣ⁺³ - 3ˣ⁺² = 162
3ˣ⁺².(3 - 1) = 162
3ˣ⁺².2 = 162
3ˣ⁺² = 162 : 2
3ˣ⁺² = 81
3ˣ⁺² = 3⁴
x + 2 = 4
x = 4 - 2
x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^x\cdot16^2=1024\)
\(\Leftrightarrow2^x=4\)
hay x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
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124 + |13 + x|*2 = 162
=> |13 + x|*2 = 38
=> |13 + x| = 19
=> 13 + x = 19 hoặc 13 + x = -19
=> x = 6 hoặc x = -32
vậy_
![](https://rs.olm.vn/images/avt/0.png?1311)
162:(x-2)^2=2
(x-2)^2=162:2
(x-2)^2=81
(x-2)^2=9^2
x-2 =9
x = 9+2
x=11
vậy x=11 :o
162:(x-2)\(^2\)=2
(x-2)\(^2\)=162:2
(x-2)\(^2\)=81
(x-2)\(^2\)=9\(^2\)
x-2=9
x = 9+2
x=11
vậy x=11