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25-2 : (3/5-1/2) + (5/2 +1/5 * 1/4 )
= 25 - 2 : 1/10 + (5/2 + 1/20)
= 25 - 20 + 51/20
= 5 + 51/20
= \(5\frac{51}{20}\)
( 3/10+ 4/5 *1/2 ) : (17/9 -4/3 : 3)
= (3/10 + 2/5) : (17/9 - 4/9)
= (-1/10) : 13/9
= -9/130
\(\frac{9}{2}\) \(-\) ( \(x\) \(-\) \(\frac{3}{4}\) ) = \(\frac{25}{4}\)
\(x\) \(-\) \(\frac{3}{4}\) = \(\frac{9}{2}\) \(-\) \(\frac{25}{4}\)
\(x\) \(-\) \(\frac{3}{4}\) = \(-\frac{7}{4}\)
\(x\) = \(-\frac{7}{4}\) \(+\) \(\frac{3}{4}\)
\(x\) = \(-1\)
\(4\) \(+\) \(x\) \(+\) \(\frac{3}{4}\) = \(\frac{17}{2}\)
( \(4\) \(+\) \(\frac{3}{4}\)) \(+\)\(x\) = \(\frac{17}{2}\)
\(\frac{19}{4}\) \(+\) \(x\) = \(\frac{17}{2}\)
\(x\) = \(\frac{17}{2}\) \(-\) \(\frac{19}{4}\)
\(x\) = \(\frac{15}{4}\)
\(\frac{3}{7}\times\frac{1}{3}+\frac{3}{7}\times\frac{4}{3}-\frac{3}{7}\times\frac{1}{9}\)
\(\frac{3}{7}\times\left(\frac{1}{3}+\frac{4}{3}-\frac{1}{9}\right)\)
\(\frac{3}{7}\times\left(\frac{5}{3}-\frac{1}{9}\right)\)
\(\frac{3}{7}\times\left(\frac{45}{27}-\frac{3}{27}\right)\)
\(\frac{3}{7}\times\frac{14}{9}\)
\(\frac{2}{3}\)
\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}:\frac{5}{6}\)
\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}\times\frac{6}{5}\)
\(\left(\frac{7}{15}+\frac{3}{5}-\frac{17}{30}\right)\times\frac{6}{5}\)
\(\left(\frac{14}{30}+\frac{18}{30}-\frac{17}{30}\right)\times\frac{6}{5}\)
\(\frac{1}{2}\times\frac{6}{5}\)
\(\frac{3}{5}\)
Chúc bạn học tốt !!!
37×13+37×43−37×1937×13+37×43−37×19
37×(13+43−19)37×(13+43−19)
37×(53−19)37×(53−19)
37×(4527−327)37×(4527−327)
37×14937×149
23
Bài 1:
câu a: 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)
= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)
= \(\dfrac{29}{6}\)
b, (15,25 + 3,75) \(\times\) 4 + ( 20,71 + 5,29)\(\times\) 5
= 19 \(\times\) 4 + 26 \(\times\) 5
= 76 + 130
= 206
c, \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{3}\) - \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{4}\)
= \(\dfrac{2}{5}\) + \(\dfrac{4}{15}\) - \(\dfrac{1}{5}\)
= \(\dfrac{6}{15}\) + \(\dfrac{4}{15}\) - \(\dfrac{3}{15}\)
= \(\dfrac{7}{15}\)
d, 1\(\dfrac{5}{7}\) + 7\(\dfrac{3}{6}\) + 2\(\dfrac{2}{7}\) - 4\(\dfrac{3}{6}\)
= (1 + 2 + \(\dfrac{5}{7}\) + \(\dfrac{2}{7}\)) + ( 7 + \(\dfrac{3}{6}\) - 4 - \(\dfrac{3}{6}\))
= 3 + 1 + 3
= 7
`@` `\text {Ans}`
`\downarrow`
`1/3+6/9+4/5+5/25`
`= 1/3+2/3+4/5+1/5`
`= 1+1`
`= 2`
`4/7*2/5+4/7*3/5-1/7`
`= 4/7*(2/5+3/5)-1/7`
`= 4/7*1-1/7`
`= 4/7-1/7=3/7`
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