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1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9=135
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\(=\dfrac{2-1}{1x2}+\dfrac{3-2}{2x3}+\dfrac{4-3}{3x4}+...+\dfrac{10-9}{9x10}=\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}=\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
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\(\frac{1}{2}+\frac{1}{3}=\frac{1.3}{2.3}+\frac{1.2}{2.3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}\)
\(\frac{7}{8}+\frac{2}{9}=\frac{63}{72}+\frac{16}{72}=\frac{79}{72}\)
\(\frac{17}{9}-\frac{11}{9}=\frac{6}{9}=\frac{2}{3}\)
\(\frac{1}{2}:\frac{1}{3}=\frac{1}{2}.\frac{3}{1}=\frac{3}{2}\)
\(\frac{1}{8}x\frac{7}{8}=\frac{7}{64}\)
Ủng hộ nhé !
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a) \(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}\)
\(=1-\frac{1}{4}\)
\(=\frac{3}{4}\)
b) \(\frac{4}{7}\times\frac{8}{9}+\frac{4}{7}\times\frac{1}{9}\)
\(=\frac{4}{7}\times\left(\frac{8}{9}+\frac{1}{9}\right)\)
\(=\frac{4}{7}\times1\)
\(=\frac{4}{7}\)
c) \(\frac{13}{6}\times\frac{3}{8}-\frac{3}{8}\times\frac{7}{6}\)
\(=\frac{3}{8}\times\left(\frac{13}{6}-\frac{7}{6}\right)\)
\(=\frac{3}{8}\times1\)
\(=\frac{3}{8}\)
d) \(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{9x10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
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1.
\(\frac{3}{5}+\left\{\frac{2}{8}+\frac{2}{5}+\frac{6}{8}\right\}\)
\(=\frac{3}{5}+\left(\frac{10}{40}+\frac{36}{40}+\frac{30}{40}\right)\)
\(=\frac{3}{5}+\frac{76}{40}\)
\(=\frac{24}{40}+\frac{76}{40}\)
\(=\frac{100}{40}=\frac{5}{2}\)
2.
\(3\frac{2}{9}-\left\{1\frac{5}{8}+1\frac{2}{9}\right\}\)
\(=\frac{29}{9}-\left\{\frac{13}{8}+\frac{11}{9}\right\}\)
\(=\frac{29}{9}-\left\{\frac{117}{72}+\frac{88}{72}\right\}\)
\(=\frac{29}{9}-\frac{205}{72}\)
\(=\frac{232}{72}-\frac{205}{72}\)
Chúc cậu học tốt !!!
\(=\frac{27}{72}=\frac{3}{8}\)
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bằng 89/72 nhé
= 89/72 nhé.