So sánh:
a. 195/1890 và 39/379
b. 193/310 và 173/350
K
Khách
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RG
1
11 tháng 7 2017
a) ta có: \(\frac{195}{1890}=\frac{73950}{716310}\)(1)
\(\frac{39}{379}=\frac{73710}{716310}\)(2)
từ 1 và 2 => \(\frac{73950}{716310}>\frac{73710}{713610}\)=> \(\frac{195}{1890}>\frac{39}{379}\)
RG
1
21 tháng 5 2022
a: 39/379=195/1895<195/1890
b: \(\dfrac{193}{310}=\dfrac{6755}{10850}\)
\(\dfrac{172}{350}=\dfrac{5332}{10850}\)
mà 6755>5332
nên 193/310>172/350
8 tháng 7 2017
Các câu dễ bạn tự làm nha:
\(\dfrac{a}{b}< 1\Rightarrow\dfrac{a+m}{b+m}< 1\left(m\in N\right)\)
\(A=\dfrac{2017^{2017}+1}{2017^{2018}+1}< 1\)
\(A< \dfrac{2017^{2017}+1+2016}{2017^{2018}+1+2016}\Rightarrow A< \dfrac{2017^{2017}+2017}{2017^{2018}+2017}\Rightarrow A< \dfrac{2017\left(2017^{2016}+1\right)}{2017\left(2017^{2017}+1\right)}\Rightarrow A< \dfrac{2017^{2016}+1}{2017^{2017}+1}=B\)\(A< B\)
22 tháng 7 2016
So sánh phân số bằng cách so sánh phần hơn với đơn vị của phân số:
Ta có: 195/193 - 1 = 195/193 - 193/193 = 2/193
và 2009/2007 - 1 = 2009/2007 - 2007/2007 = 2/2007
Vì: 2/2007 < 2/193 nên 2009/2007 < 195/193
22 tháng 7 2016
Ta có :
\(\frac{195}{193}\)- 1 = \(\frac{2}{193}\)
\(\frac{2009}{2007}\)= \(\frac{2}{2007}\)
Vì \(\frac{2}{193}>\frac{2}{2007}\)nên \(\frac{195}{193}>\frac{2009}{2007}\)
TL
11 tháng 3 2016
a) 1763/1765>191/193;
171/172<1090/1091;
576/579<195/196
b) 1385/1386>176/177;
185/187<1070/1071
TV
0
NT
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1
\(\frac{195}{1890}>\frac{39}{379}\)
\(\frac{193}{310}>\frac{173}{350}\)
\(k-mk-nha\)