Question

[Trần Thị Quỳnh Anh]

(8x-16).(x-4³)=0

Ai trả lời đúng thì tui tick cho:))))))))))

Answer 1

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`@` `\text {Ans}`

`\downarrow`

\(\left(8x-16\right)\cdot\left(x-4^3\right)=0\)

\(\Rightarrow\) \(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}8x=16\\x=64+0\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=16\div8\\x=64\end{matrix}\right.\)

`\Rightarrow`\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)

Vậy, \(x\in\left\{2;64\right\}\)

Answer 2

[Nguyễn Thị Thương Hoài]

(8\(x\) -16)(\(x-4^3\)) = 0

\(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}8x=16\\x=64\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)

Vậy \(x\in\) { 2; 64}