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29 tháng 12 2022

a,(-7)+3x(-25)

= (-7)+(-75)

=(-82)

b, (-2)x3mũ 2+(-4)-5x0+7x2021 mũ 0

=(-2) x9+(-4)-5x7x1

= (-18)+(-4)-35

= (-22)-35

= (-57)

29 tháng 12 2022

a) (-7) + 3x(-25)

= (-7)+(-75)

=(-82)

b)(-2)x3mu2 + (-4)-5x0 + 7x2021mu0

=(-2) x9 + (-4) -5 x 7 x 1

= (-18)+(-4) -35

= (-22) -35

=(-57)

5 tháng 12 2017

nik lộn

2x+1. 22009 = 22010

10 - 2x = 25 - 3x

2 tháng 6 2017

a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)

\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)

b) \(\dfrac{39}{7}:x=13\)

\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)

c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)

\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)

\(\dfrac{14}{5}x=34+50=84\)

\(x=\dfrac{84}{\dfrac{14}{5}}=30\)

d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)

e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)

\(\dfrac{1}{6}x=\dfrac{5}{12}\)

\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)

g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)

\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)

\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)

\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)

\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)

h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)

\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)

\(x=1\)

Mỏi tay woa bn làm nốt nha!!

a) Ta có: \(\frac{x-17}{33}+\frac{x-21}{29}+\frac{x}{25}=4\)

\(\Leftrightarrow\frac{x-17}{33}-1+\frac{x-21}{29}-1+\frac{x}{25}-2=0\)

\(\Leftrightarrow\frac{x-17-33}{33}+\frac{x-21-29}{29}+\frac{x-2\cdot25}{25}=0\)

\(\Leftrightarrow\frac{x-50}{33}+\frac{x-50}{29}+\frac{x-50}{25}=0\)

\(\Leftrightarrow\left(x-50\right)\left(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}\right)=0\)

\(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}>0\)

nên x-50=0

hay x=50

Vậy: x=50

b) Ta có: \(\left(3x-5\right)\left(7-5x\right)+\left(5x+2\right)\left(3x-2\right)=2\)

\(\Leftrightarrow-15x^2+46x-35+15x^2-4x-4-2=0\)

\(\Leftrightarrow42x-41=0\)

\(\Leftrightarrow42x=41\)

hay \(x=\frac{41}{42}\)

17 tháng 3 2020

a, \(\frac{x-17}{33}+\frac{x-21}{29}+\frac{x}{25}=4\)

\(\Leftrightarrow\left(\frac{x-17}{33}-1\right)+\left(\frac{x-21}{29}-1\right)+\left(\frac{x}{25}-2\right)=4-4\)

\(\Leftrightarrow\left(\frac{x-17-33}{33}\right)+\left(\frac{x-21-29}{29}\right)+\left(\frac{x-2.25}{25}\right)=0\)

\(\Leftrightarrow\frac{x-50}{33}+\frac{x-50}{29}+\frac{x-50}{25}=0\)

\(\Leftrightarrow\left(x-50\right)\left(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}\right)=0\) (*)

\(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}>0\Rightarrow\) Phương trình (*) xảy ra khi: \(x-50=0\Leftrightarrow x=50\)

Vậy phương trình có nghiệm duy nhất là x = 50.

29 tháng 1 2019

a. x- (17 - x) = x-7

x-17+x = x+7

2x-17=x+7

2x-x= 7+17

x= 24

b. 9-25=(7-x)-(25+7)

-16=7-x-25-7

-16=-x-25

x= -25 + 16

x = -9

c. (-12)^2 .x = 56 + 10.13.x

144x = 56 + 130x

144x - 130x = 56

14x=56

x= 56 : 14

x= 4

d. 4/24 : (3x-2) = -3

4/24 = -3.(3x-2)

4/24 = -9x + 6

9x = 6 - 4/24

9x = 35/6

x= 35/6 :9

x= 35/54

e. 5/-45 chia hay nhân với (-3-2x) nhỉ

30 tháng 1 2019

chia bạn nhé

14 tháng 12 2021

\(a,=\dfrac{\left(x-5\right)\left(x+5\right)\left(3x-7\right)}{2\left(x+5\right)}=\dfrac{\left(x-5\right)\left(3x-7\right)}{2}\\ b,=\dfrac{\left(x-2\right)\left(x+2\right)}{x\left(x-1\right)}\cdot\dfrac{x-1}{x\left(x+2\right)}=\dfrac{x-2}{x^2}\)

14 tháng 12 2021

a) \(\left(x^2-25\right):\dfrac{2x+10}{3x-7}=\left(x-5\right)\left(x+5\right).\dfrac{3x-7}{2\left(x+5\right)}=\dfrac{\left(x-5\right)\left(3x-7\right)}{2}\)

b) \(\dfrac{x^2-4}{x^2-x}:\dfrac{x^2+2x}{x-1}=\dfrac{\left(x-2\right)\left(x+2\right)}{x\left(x-2\right)}.\dfrac{x-1}{x\left(x+2\right)}=\dfrac{x-1}{x^2}\)

7 tháng 4 2017

a) 0,5 x - \(\frac{2}{3}\)x = \(\frac{7}{12}\)

   x . ( 0,5 - \(\frac{2}{3}\)) = \(\frac{7}{12}\)

   x .  \(\frac{-1}{6}\)        = \(\frac{7}{12}\)

   x                         = \(\frac{7}{12}\)\(\frac{-1}{6}\)

   x                          = \(\frac{-7}{2}\)

b) x : \(\frac{25}{3}\)      = -25 

    x                     = -25 . \(\frac{25}{3}\)

     x                    = \(\frac{-625}{3}\)

c) 5,5 x = \(\frac{13}{15}\)

          x = \(\frac{13}{15}\): 5,5

           x = \(\frac{26}{165}\)

d) (\(\frac{3x}{7}\)+ 1 ) : ( -4) = \(\frac{-1}{28}\)

   ( \(\frac{3x}{7}\)+ 1 )           = \(\frac{-1}{28}\). ( -4)

 \(\frac{3x}{7}\)+ 1                 = \(\frac{1}{7}\)

 \(\frac{3x}{7}\)                       = \(\frac{1}{7}\)- 1

  \(\frac{3x}{7}\)                      = \(\frac{-6}{7}\)

=> x = -2

e) y + 30% y =  -1,3

   y + \(\frac{3}{10}\)y = -1,3

  y . ( 1 + \(\frac{3}{10}\)) = -1,3

y .       \(\frac{13}{10}\)     = -1,3

y                          = -1,3 : \(\frac{13}{10}\)

y                          = -1

g) y - 25% y = \(\frac{1}{2}\)

    y - \(\frac{1}{4}\)y = \(\frac{1}{2}\)

    y . ( 1 - \(\frac{1}{4}\)) = \(\frac{1}{2}\)

    y   . \(\frac{3}{4}\)  = \(\frac{1}{2}\)

     y                = \(\frac{1}{2}\)\(\frac{3}{4}\)

     y                  = \(\frac{2}{3}\)

ai tốt bụng thì tk cho mk nha, mk đg âm điểm đây huhu

16 tháng 11 2021

a: \(x\in\left\{0;25\right\}\)

c: \(x\in\left\{0;5\right\}\)

22 tháng 6 2016

\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

   =  \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

    = \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)

     = \(\frac{1}{4}+\frac{1}{2}\)

      =  \(\frac{3}{4}\)

b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)

    =\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)

   = \(-\frac{35}{27}+\frac{47}{21}\)

   =        \(\frac{178}{189}\)

c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)

  = \(\frac{117}{13}-\frac{311}{65}\)

 =       \(\frac{274}{65}\)

d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)

\(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)

\(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)

=     \(\frac{1}{3}+\frac{5}{2}\)

=         \(\frac{17}{6}\)