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\(a,2^x.4=128\)

\(\Leftrightarrow2^x=128:4\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Rightarrow x=5\)

\(b,2^x=4.128\)

\(\Leftrightarrow2^x=2^2.2^7\)

\(\Leftrightarrow2^x=2^9\)

\(\Rightarrow x=9\)

\(c,3^x=3^3.3^5\)

\(\Leftrightarrow3^x=3^8\)

\(\Rightarrow x=8\)

\(d,2^x.\left(2^2\right)^3=\left(2^3\right)^2\)

\(\Leftrightarrow2^x.2^6=2^6\)

\(\Leftrightarrow2^x=2^6:2^6\)

\(\Leftrightarrow2^x=1\)

\(\Rightarrow x=0\)

24 tháng 7 2021

Trả lời:

a, 2x . 4 = 128

=> 2x = 32

=> 2x = 25

=> x = 5

b, 2x = 4.128

=> 2x = 512

=> 2x = 29

=> x = 9

c, 3x = 33 . 35 

=> 3x = 38

=> x = 8

d, 2x ( 22 )3 = ( 23 )2

=> 2x . 26 = 26

=> 2x = 1

=> 2x = 20

=> x = 0

b: Ta có: \(2^{x+3}+2^x=144\)

\(\Leftrightarrow2^x\cdot9=144\)

\(\Leftrightarrow2^x=16\)

hay x=4

14 tháng 10 2021

a) (x ^ 54)^2 = x                                         

         x^108  = x

Để: x^108  = x 

=> x=0 hoặc x=1

12 tháng 10 2021

Bài 1

a) \(x=x^5\)

\(x^5-x=0\)

\(x\left(x^4-1\right)=0\)

\(x=0\) hoặc \(x^4-1=0\)

\(x^4-1=0\)

\(x^4=1\)

\(x=1\)

Vậy x = 0; x = 1

b) \(x^4=x^2\)

\(x^4-x^2=0\)

\(x^2\left(x^2-1\right)=0\)

\(x^2=0\) hoặc \(x^2-1=0\)

*) \(x^2=0\)

\(x=0\)

*) \(x^2-1=0\)

\(x^2=1\)

\(x=1\)

Vậy \(x=0\)\(x=1\)

c) \(\left(x-1\right)^3=x-1\)

\(\left(x-1\right)^3-\left(x-1\right)=0\)

\(\left(x-1\right)\left[\left(x-1\right)^2-1\right]=0\)

\(x-1=0\) hoặc \(\left(x-1\right)^2-1=0\)

*) \(x-1=0\)

\(x=1\)

*) \(\left(x-1\right)^2-1=0\)

\(\left(x-1\right)^2=1\)

\(x-1=1\) hoặc \(x-1=-1\)

**) \(x-1=1\)

\(x=2\)

**) \(x-1=-1\)

\(x=0\)

Vậy \(x=0\)\(x=1\)\(x=2\)

 

18 tháng 8 2021

Bài 3 :

a) 4.(x-5) - 2 3=24.3

4x-20-8=48

4x=76

x=19

b) 4.x3+15=271

4.x3=256

x3=64

=> x=4

c) ( 2x-3)2= 169

=> 2x-3= 13

2x=16

x=8

 Chúc bạn học tốt !

18 tháng 8 2021

4*(x-5) - 2^3 = 2^4*3 

4*(x-5) - 8 = 16*3 

4*(x-5) - 8 = 48 

4*(x-5) = 48 + 8 

4*(x-5) = 56 

x- 5 = 56 : 4 

x - 5 = 14 

x = 14 + 5 

x = 19 

14 tháng 10 2018

Bo may la binh day k di hieu ashdbfgbgygygggydfsghuyfhdguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu3

20 tháng 9 2017

Bài 1 :

a) 2x-64=26

=> 2x-26=26

2x=26+26 (26+6)

2x = 212

<=> x = 12

b) 2x:16=128

=> 2x.24 = 27

2x = 27:24 (27-4)

2x = 23

<=> x=3

Bài 2 :

b) A= 82 = (23)2 = 26  

B= 26

=> A = B ( 26=26 )

c) A= 35 = 243

B = 28 = 256

=> A < B ( 243 < 256 )

8 tháng 8 2023

a/

\(x^3-4x^2-\left(x-4\right)=0\)

\(\Leftrightarrow x^2\left(x-4\right)-\left(x-4\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(x^2-1\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(x-1\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-1=0\\x+1=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=1\\x=-1\end{matrix}\right.\)

b/

\(x^5-9x=0\)

\(\Leftrightarrow x\left(x^4-9\right)=x\left(x^2-3\right)\left(x^2+3\right)=0\)

\(\Leftrightarrow x\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)

c/

\(\left(x^3-x^2\right)^2-4x^2+8x-4=0\)

\(\Leftrightarrow x^4\left(x-1\right)^2-4\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(x-1\right)^2\left(x^4-4\right)=0\)

\(\Leftrightarrow\left(x-1\right)^2\left(x^2-2\right)\left(x^2+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x^2-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\pm\sqrt{2}\end{matrix}\right.\)

8 tháng 8 2023

Sos

 

14 tháng 10 2018

a) 2: 4 = 128

=> 2x  = 512

=> 2x  = 29

=> x = 9

b) x15 = x

=> x15  = x15

=> x = 1 hoặc 0

c) ( 2x + 1 )3 = 125

=> ( 2x + 1 )3 = 53

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

14 tháng 10 2018

a) 2: 4 = 128

=> 2x = 128 . 4

=> 2x = 512

=> 2x = 29

=> x = 9

b) x15 = x

=> x15 = x15

=> x = 1 hoặc 0

c) ( 2x + 1 )3 = 125

=> ( 2x + 1 )3 = 53

=> 2x + 1 = 5

=> 2x = 5 - 1

=> 2x = 4

=> x = 4 : 2

=> x = 2