tìm x
\(\frac{2xx-4,36}{0,125}\)=8
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HG
1
6 tháng 7 2023
\(\dfrac{2\times x-4,36}{0,125}=0,25\times42,9-11,7\times0,25+0,25\times0,8\)
\(\dfrac{2\times x-4,36}{0,125}=0,25\times\left(42,9-11,7+0,8\right)\)
\(\dfrac{2\times x-4,36}{0,125}=0,25\times32=8\)
\(2\times x-4,36=8\times0,125=1\)
\(2\times x=1+4,36=5,36\)
\(x=5,36\div2\)
\(x=2,68\)
T
29 tháng 5 2019
#)Giải :
a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8
\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )
\(\frac{2xX-4,36}{0,125}=\)0,25 x 32
\(\frac{2xX-4,36}{0,125}=8\)
\(2xX-4,36=8x0,125\)
\(2xX-4,36=1\)
\(2xX=1+4,36\)
\(2xX=5,36\)
\(X=5,36:2\)
\(X=2,68\)
#~Will~be~Pens~#
DN
1
11 tháng 7 2016
\(\frac{2x-4.36}{0.125}=0.25\cdot42.9-11.7\cdot0.25+0.25\cdot0.8\)
\(\frac{2x-4.36}{0.125}=0.25\left(42.9-11.7+0.8\right)\)
\(\frac{2x-4.36}{0.125}=0.25\cdot32\)
\(\frac{2x-4.36}{0.125}=8\)
2x - 4.36 = 8 * 0.125 = 1
2x = 1 + 4.36 = 5.36
x = 5.36 : 2 = 2.68
PT
0
18 tháng 5 2016
\(2x-\frac{4.36}{0.125}=0.15\times42.9-11.7\times0,25\times0.8\)
\(2x-\frac{872}{25}=\frac{819}{200}\)
\(2x=\frac{819}{200}+\frac{872}{25}=\frac{1559}{40}\)
\(x=\frac{1559}{40}\times\frac{1}{2}=\frac{1559}{80}\)
3 tháng 1 2018
2xX+X:0,125=10
2xX+Xx1/8=10
Xx(2+1/8)=10
Xx2,125=10
X=10:2,125
X=80/17
9 tháng 4 2015
\(\frac{4}{7}.x+0,125=1\frac{1}{8}+x\)
=>\(\frac{4}{7}.x+\frac{1}{8}=1+x+\frac{1}{8}\)
=>\(\frac{4}{7}.x=1+x\)
=>\(\frac{4}{7}.x-x=1\)
=>\(\left(\frac{4}{7}-1\right)x=1\)
=>\(\frac{-3}{7}.x=1\)
=>\(x=1:\frac{-3}{7}=\frac{1.7}{-3}=-\frac{7}{3}\)
TT
31 tháng 7 2020
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
31 tháng 7 2020
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
