Tinh 2015/2016:(0,4-2/9+2/11 phan 1,4-7/9+7/11x-1va 1/6+0,875-0,7 phan 1/3-0,25+1/5)
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NM
1
CH
0
PM
19 tháng 10 2016
B=\(\left(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\right):\frac{2016}{2017}\)
\(=\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\right):\frac{2016}{2017}\)
\(=\left(\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\right):\frac{2016}{2017}\)
\(=\left(\frac{2}{7}-\frac{1}{\frac{7}{2}}\right):\frac{2016}{2017}=\left(\frac{2}{7}-\frac{2}{7}\right):\frac{2016}{2017}=0\)
16 tháng 5 2022
\(=2014:\left[\dfrac{\dfrac{7}{6}+\dfrac{7}{8}-\dfrac{7}{10}}{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}\cdot\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}\right]\)
\(=2014:\left(\dfrac{7}{2}\cdot\dfrac{2}{7}\right)=2014\)
LM
5 tháng 8 2016
\(\Rightarrow A=\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{1+\frac{1}{6}-\frac{7}{8}+\frac{7}{10}}\right):\frac{2014}{2015}\)
\(\Rightarrow A=\left(\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{17}{60}}{\frac{119}{120}}\right):\frac{2014}{2015}\)
\(\Rightarrow A=\left(\frac{2}{7}-\frac{2}{7}\right):\frac{2014}{2015}\)
\(\Rightarrow A=0:\frac{2014}{2015}\Rightarrow A=0\)
MC
0
21 tháng 5 2017
\(M=\left(\dfrac{0,4-\dfrac{2}{9}+\dfrac{2}{11}}{1,4-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-0,25+\dfrac{1}{5}}{1\dfrac{1}{6}-0,875+0,7}\right):\dfrac{2014}{2015}\)
\(=\left[\dfrac{2\left(0,2-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(0,2-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{2\left(\dfrac{1}{6}-0,125+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{7}-0,125+\dfrac{1}{10}\right)}\right]:\dfrac{2014}{2015}\)
\(=\left(\dfrac{2}{7}-\dfrac{2}{7}\right):\dfrac{2014}{2015}=0:\dfrac{2014}{2015}=0\)
Vậy M = 0
NN
18 tháng 10 2020
\(M=\left(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\right):\frac{2014}{2015}\)
\(=\left(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\right):\frac{2014}{2015}\)
\(=\left[\frac{2.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\right].\frac{2015}{2014}\)
\(=\left(\frac{2}{7}-\frac{1}{\frac{7}{2}}\right).\frac{2015}{2014}=\left(\frac{2}{7}-\frac{2}{7}\right).\frac{2015}{2014}=0\)
XO
18 tháng 10 2020
Ta có M = \(\left(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\right):\frac{2014}{2015}\)
= \(\left(\frac{2\left(0,2-\frac{1}{9}+\frac{1}{11}\right)}{7\left(0,2-\frac{1}{9}+\frac{1}{11}\right)}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-0,25+\frac{1}{5}\right)}\right):\frac{2014}{2015}\)
= \(\left(\frac{2}{7}-\frac{1}{\frac{7}{2}}\right):\frac{2014}{2015}=\left(\frac{2}{7}-\frac{2}{7}\right):\left(\frac{2014}{2015}\right)=0\)
