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Gọi số có 5 chữ số cần tìm là x (x ∈ N; 10000 ≤ x ≤ 99999)

Khi thêm 1 vào bên phải số đó ta được số mới là số có 6 chữ số với chữ số hàng đơn vị là 1:

Khi đó số đã cho là số chục và số mới được viết là: 10x + 1.

Khi thêm 1 vào bên trái số đó ta được số mới là số có 6 chữ số với chữ số hàng trăm nghìn là 1

Khi đó số đã cho là số đơn vị và số mới được viết là: 100000 + x.

Theo đề bài ra nếu viết thêm 1 vào bên phải số đó thì được một số lớn gấp ba lần số nhận được khi ta viết thêm 1 vào bên trái số đó nên ta có phương trình

10x + 1 = 3(100000 + x)

⇔ 7x = 299999

⇔ x = 42857 (tmđk)

Vậy số cần tìm là 42857

23 tháng 8 2021

Gọi số có 5 chữ số cần tìm là x (x ∈ N; 10000 ≤ x ≤ 99999)

Khi thêm 1 vào bên phải số đó ta được số mới là số có 6 chữ số với chữ số hàng đơn vị là 1:

Khi đó số đã cho là số chục và số mới được viết là: 10x + 1.

Khi thêm 1 vào bên trái số đó ta được số mới là số có 6 chữ số với chữ số hàng trăm nghìn là 1

Khi đó số đã cho là số đơn vị và số mới được viết là: 100000 + x.

Theo đề bài ra nếu viết thêm 1 vào bên phải số đó thì được một số lớn gấp ba lần số nhận được khi ta viết thêm 1 vào bên trái số đó nên ta có phương trình

10x + 1 = 3(100000 + x)

⇔ 7x = 299999

⇔ x = 42857 (tmđk)

Vậy số cần tìm là 42857

* Nguồn : Hoc 24 *

22 tháng 7 2015

Gọi số đó là x ta có pt:

10x+1=3.(100000+x)\(\Rightarrow\)x=42857

42857                    

12 tháng 8 2016

Gọi số đó là abc.Ta có:

              abc8=2*1abc

=>abc*10+8=2*1000+2*abc

=>abc*10-abc*2=2000-8

=>abc*8=1992

=>abc=1992:8

=>abc=249

Vậy số cần tìm là 249

12 tháng 8 2016

Gọi số cần tìm là abc:

Ta có:

abc8 = 2 x 1abc

abc x 10 + 8 = 2000 x abc + 2 x abc

abc x 10 - abc x 2 = 2000 - 8

abc x 8 = 1992 

abc = 1992 : 8

abc = 249

Vậy số cần tìm là 249

11 tháng 4 2018

Gọi số phải tìm là ab

Ta có :1ab=ab.3

=>100+ab=ab.3

=>ab.3-ab=100

=>ab.(3-1)=100

=>ab.2=100

=>ab=100:2

=>ab=50

vậy ab =50

12 tháng 4 2018

Gọi số phải tìm là ab

Ta có :

1ab=ab.3

=>100+ab=ab.3

=>ab.3-ab=100

=>ab.(3-1)=100

=>ab.2=100

=>ab=100:2

=>ab=50

Vậy ab =50

2 tháng 5 2015

Gọi 3 số là abc

theo đb ta có

abc1=3  x  2abc

abc x 10   +1 =3x 2000+3abc

7 abc= 5999

abc=857 

vậy số đó là 857

20 tháng 10 2018

 857 dung 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1. Tìm một số tự nhiên có 2 chữ số, biết rằng nếu thêm chữ số 7 vào bên trái số đó ta được một số lớn gấp 36 lần số đã cho. 2. Tìm một số có 3 chữ số, biết rằng khi viết thêm số 30 vào bên trái số đó ta được một số lớn gấp 151 lần số phải tìm.3. Tìm một số có 2 chữ số, biết rằng khi viết thêm chữ số 5 vào bên phải số đó ta được số lớn hơn số phải tìm 554 đơn vị.4. Tìm một số...
Đọc tiếp

1. Tìm một số tự nhiên có 2 chữ số, biết rằng nếu thêm chữ số 7 vào bên trái số đó ta được một số lớn gấp 36 lần số đã cho. 

2. Tìm một số có 3 chữ số, biết rằng khi viết thêm số 30 vào bên trái số đó ta được một số lớn gấp 151 lần số phải tìm.

3. Tìm một số có 2 chữ số, biết rằng khi viết thêm chữ số 5 vào bên phải số đó ta được số lớn hơn số phải tìm 554 đơn vị.

4. Tìm một số có 2 chữ số, biết rằng khi viết thêm số 78 vào bên phải số đó ta được số lớn hơn số phải tìm 1266 đơn vị.

5. Khi viết thêm số 85 vào bên phải một số tự nhiên có 3 chữ số thì số đó tăng thêm 43348 đơn vị. Tìm số có 3 chữ số đó.

6. Khi viết thêm số 65 vào bên phải một số tự nhiên thì số đó tăng thêm 78176 đơn vị. Tìm số đó.

7. Khi viết thêm số 56 vào bên phải một số tự nhiên thì số đó tăng thêm 122222 đơn vị. Tìm số đó.

1
10 tháng 12 2021

\(1,\Rightarrow\overline{7ab}=36\cdot\overline{ab}\Rightarrow\overline{ab}+700=36\cdot\overline{ab}\\ \Rightarrow35\cdot\overline{ab}=700\Rightarrow\overline{ab}=20\\ 2,\Rightarrow\overline{30abc}=151\cdot\overline{abc}\Rightarrow\overline{abc}+30000=151\cdot\overline{abc}\\ \Rightarrow\overline{abc}\cdot150=30000\Rightarrow\overline{abc}=200\\ 3,\Rightarrow\overline{ab5}=10\cdot\overline{ab}+5=554+\overline{ab}\\ \Rightarrow\overline{ab}\cdot9=549\Rightarrow\overline{ab}=61\\ 4,\Rightarrow\overline{ab78}=\overline{ab}\cdot100+78=1266+\overline{ab}\\ \Rightarrow\overline{ab}\cdot99=1188\Rightarrow\overline{ab}=12\\ 5,\Rightarrow\overline{abc85}=\overline{abc}\cdot100+85=43348+\overline{abc}\\ \Rightarrow\overline{abc}\cdot99=43263\Rightarrow\overline{abc}=437\\ 6,7,\text{Đề thiếu}\)

10 tháng 12 2021

thank you

 

3 tháng 5 2018

Gọi số có 5 chữ số cần tìm là x (x ∈ N; 10000 ≤ x ≤ 99999)

Khi thêm 1 vào bên phải số đó ta được số mới là số có 6 chữ số với chữ số hàng đơn vị là 1:

Khi đó số đã cho là số chục và số mới được viết là: 10x + 1.

Khi thêm 1 vào bên trái số đó ta được số mới là số có 6 chữ số với chữ số hàng trăm nghìn là 1

Khi đó số đã cho là số đơn vị và số mới được viết là: 100000 + x.

Theo đề bài ra nếu viết thêm 1 vào bên phải số đó thì được một số lớn gấp ba lần số nhận được khi ta viết thêm 1 vào bên trái số đó nên ta có phương trình

10x + 1 = 3(100000 + x)

⇔ 7x = 299999

⇔ x = 42857 (tmđk)

Vậy số cần tìm là 42857

10 tháng 7 2015

a, Gọi số đó là ab(có gạch trên đầu) đk ab thuộc N

Theo đề bài ta có 

9ab=ab.13

900+10a+b=(10a+b).13

900+10a+b=130a+13b

900=120a+12b

Ta có a=7 vì a<7 thì 12b=180 vậy b=15 ko thỏa mãn a=8,9 cũng ko thỏa mãn

từ đó 12b=900-840=60

Vậy b=60:12

b=5

Vậy số đó là 75

b Gọi số đó là abc(có gạch trên đầu) đk abc thuộc N và a,b,c thuộc N a khác 0

Nếu viết thêm chữ số 5 vào bên phải số đó thì tức là đã gấp số đó lên 10 lần và 5 đơn vị

9.abc=1112-5

9.abc=1107

Vậy abc=1107:9

abc=123 Vậy số đó là 123

 

12 tháng 10 2015

b) Gọi số cần tìm là abc

theo đề ta có abc5= abc+1112

=> abc.10+5=abc+1112

=> abc.9=1112-5

=> abc.9=1107

=> abc=1107chia 5

=> abc=123