bài 2 tìm x
a,\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
b,\(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
c,\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)
d,\(\frac{3}{5}+\frac{4}{9}:x=\frac{2}{3}\)
e,\(\left|x+75\%\right|=2\frac{1}{5}\)
i,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2.x\right)=0\)
k,\(\frac{4}{7}.x-\frac{2}{3}=\frac{1}{5}\)
l,\(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)
m,\(\left|2.x-\frac{1}{3}\right|+\frac{5}{6}=1\)
n,\(\frac{1}{3}-\frac{7}{8}.x=\frac{1}{3}\)
11,\(\frac{x+2}{5}=\frac{7}{12}-1\frac{1}{4}\)
12,\(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
13,\(\frac{2}{5}+\frac{3}{5}.\left(3.x-3,7\right)=-\frac{53}{10}\)
14,\(\frac{7}{9}:\left(2+\frac{3}{4}.x\right)+\frac{5}{9}=\frac{23}{27}\)
a, Ta có:
\(2.x-\frac{1}{2}=\frac{5}{4}-\frac{1}{2}.x\)
\(\Leftrightarrow2.x+\frac{1}{2}.x=\frac{5}{4}+\frac{1}{2}\)
\(\Leftrightarrow\frac{5}{2}.x=\frac{7}{4}\)
\(\Leftrightarrow x=\frac{7}{10}\). Vậy: \(x=\frac{7}{10}\)
b, Ta có:
\(\frac{3}{4}-\frac{5}{2}.x=2-3.x\)
\(\Leftrightarrow2-\frac{3}{4}=3.x-\frac{5}{2}.x\)
\(\Leftrightarrow\frac{5}{4}=\frac{1}{2}.x\)
\(\Leftrightarrow x=\frac{5}{2}\). Vậy: \(x=\frac{5}{2}\)
c, Ta có:
\(\frac{3}{2}.\left(x-\frac{1}{3}\right)-2.\left(x-\frac{1}{2}\right)=3\)
\(\Leftrightarrow\frac{3}{2}.x-\frac{3}{2}.\frac{1}{3}-\left(2.x-2.\frac{1}{2}\right)=3\)
\(\Leftrightarrow\frac{3}{2}.x-\frac{1}{2}-2.x+1=3\)
\(\Leftrightarrow-\frac{1}{2}.x+\frac{1}{2}=3\)
\(\Leftrightarrow-\frac{1}{2}.x=\frac{5}{2}\)
\(\Leftrightarrow x=-5\). Vậy: \(x=-5\)
d, Ta có:
\(\frac{4}{3}.\left(x-\frac{3}{2}\right)-3.\left(\frac{1}{3}.x+1\right)=6\)
\(\Leftrightarrow\frac{4}{3}.x-\frac{4}{3}.\frac{3}{2}-3.\frac{1}{3}.x-3=6\)
\(\Leftrightarrow\frac{4}{3}.x-2-x-3=6\)
\(\Leftrightarrow\frac{1}{3}.x-5=6\)
\(\Leftrightarrow\frac{1}{3}.x=11\)
\(\Leftrightarrow x=33\). Vậy: \(x=33\)
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