2.x - 138= 8.9
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
7 tháng 11 2021
2x-138 = 8.9
2x - 138 = 72
2x = 138 + 72
2x = 210
x = 210 : 2
x = 105
7 tháng 11 2021
\(2x-138=8.9\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=105\)
SD
1
28 tháng 9 2018
a.70 -5.(x-3)=45
x-3=70-5-45
x-3=20
x=20-3=17
b.2x-138=8.9
2x-138=72
2x=72+138
2x=210
x=210:2=105
c.10+2n=16
2n=16-10
2n=6
n=6:3=2
d.[(4x+28).3+55]:5=35
[(4x+28).3+55]=35x5=175
4x+28=(175-55):3
4x+28=40
4x=40-28=12
x=12:4=3
Dung thi k mk nha
Chuc bn hoc gioi nha
PQ
1
HT
3 tháng 6 2015
G=\(\frac{8.9+8.9.10+8.9+11+8.9+2}{4.6+4.6.6+4.6.4+4.6.8}\)
G=\(\frac{8.9.\left(1+10+1+1\right)+11+2}{4.6.\left(1+6+4+8\right)}\)
G=\(\frac{72.13+13}{24.19}\)
G=\(\frac{13.\left(72+1\right)}{24.19}=\frac{13.73}{24.19}\)
G=\(\frac{949}{456}\)
LP
1
20 tháng 8 2021
Ta có: \(\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow100\left(\dfrac{1}{1}-\dfrac{1}{10}\right)-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]\cdot2=89\)
\(\Leftrightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=\dfrac{1}{2}\)
\(\Leftrightarrow x+\dfrac{103}{50}=5\)
hay \(x=\dfrac{147}{50}\)
T
4
VN
Võ Ngọc Phương
CTVHS
VIP
27 tháng 12 2023
\(5\times4\times2\times25\)
\(=\left(5\times2\right)\times\left(4\times25\right)\)
\(=10\times100=1000\)
________
\(138\times8+2\times138\)
\(=138\times\left(8+2\right)\)
\(=138\times10=1380\)
27 tháng 12 2023
5×4×2×255×4×2×25
=(5×2)×(4×25)
=10×100
=1000
138×8+2×138138×8+2×138
=138×(8+2)=138×(8+2)
=138×10=1380
NT
1
HN
15 tháng 7 2019
\(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{8.9}+\frac{1}{9.10}\right)\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-........-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{10}{10}-\frac{1}{10}=\frac{9}{10}\)
\(\Leftrightarrow\frac{9}{10}.100-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right):\frac{1}{2}\right]=89\)
\(\Leftrightarrow90-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right):\frac{1}{2}\right]=89\)
\(\Leftrightarrow\frac{5}{2}:\left(x+\frac{206}{100}\right):\frac{1}{2}=90-89=1\)
\(\Leftrightarrow\frac{5}{2}:\left(x+\frac{206}{100}\right)=1.\frac{1}{2}=\frac{1}{2}\)
\(\Leftrightarrow x+\frac{206}{100}=\frac{5}{2}:\frac{1}{2}\)
\(\Leftrightarrow x+\frac{103}{50}=\frac{5}{2}.2\)
\(\Leftrightarrow x+\frac{103}{50}=5\)
\(\Leftrightarrow x=5-\frac{103}{50}\)
\(\Leftrightarrow x=\frac{250}{50}-\frac{103}{50}\)
\(\Leftrightarrow x=\frac{147}{50}\)
NT
1
DL
22 tháng 6 2018
Đặt \(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{9.10}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(A=1-\frac{1}{10}=\frac{9}{10}\)
\(\Rightarrow\frac{9}{10}.100-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=89\)
\(\Leftrightarrow90-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=89\)
\(\Rightarrow\frac{5}{2}:\left(x+\frac{206}{100}\right):\frac{1}{2}=90-89=1\)
\(\Leftrightarrow x+\frac{206}{100}=\frac{5}{2}:\frac{1}{2}:1=5\)
\(\Rightarrow x=5-\frac{206}{100}=\frac{147}{50}\)
Vậy \(x=\frac{147}{50}.\)
\(2x-138=8\cdot9\)
\(\Leftrightarrow2x-138=72\)
\(\Leftrightarrow2x=72+138\)
\(\Leftrightarrow2x=210\)
\(\Leftrightarrow x=210:2=105\)
Vậy x = 105
2.x - 138 = 8.9
=>2.x - 138 = 72
=> 2.x = 72 + 138
=> 2.x = 210
=> x = 210 : 2
=> x = 105