tính nhanh
\(\left(2^2+2^3\right):2^2\)
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\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\\=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\\ =\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\\ =\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\\ =\left(2^{16}-1\right)\left(2^{16}+1\right)\\ =2^{32}-1 \)
Ta có:
\(\begin{array}{l}M = \left( {{{10}^2} - 1} \right).\left( {{{10}^2} - {2^2}} \right).\left( {{{10}^2} - {3^2}} \right).\,\,...\left( {{{10}^2} - {{10}^2}} \right)..\,\,.\left( {100 - {{50}^2}} \right)\\ = \left( {{{10}^2} - 1} \right).\left( {{{10}^2} - {2^2}} \right).\left( {{{10}^2} - {3^2}} \right).... 0 ...\left( {100 - {{50}^2}} \right)\\ = 0\end{array}\)
\(2017\cdot \left(225-1^2\right)\left(225-2^2\right)....\left(225-15^2\right).....\left(225-56^2\right)\)
\(=2017\cdot224\cdot221\cdot\cdot\cdot\cdot\cdot0\cdot\cdot\cdot\left(-2911\right)\)
\(=0\)
`(5^(16) +16^5)(3^(17)-3^(10))(2^4-4^2)`
`=(5^(16)+16^5)(3^(17)-3^(10))(16-16)`
`=(5^(16)+16^5)(3^(17)-3^(10))0`
`=0`
Bài 1:
a.
$|x+\frac{7}{4}|=\frac{1}{2}$
\(\Leftrightarrow \left[\begin{matrix} x+\frac{7}{4}=\frac{1}{2}\\ x+\frac{7}{4}=-\frac{1}{2}\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=\frac{-5}{4}\\ x=\frac{-9}{4}\end{matrix}\right.\)
b. $|2x+1|-\frac{2}{5}=\frac{1}{3}$
$|2x+1|=\frac{1}{3}+\frac{2}{5}$
$|2x+1|=\frac{11}{15}$
\(\Leftrightarrow \left[\begin{matrix} 2x+1=\frac{11}{15}\\ 2x+1=\frac{-11}{15}\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=\frac{-2}{15}\\ x=\frac{-13}{15}\end{matrix}\right.\)
c.
$3x(x+\frac{2}{3})=0$
\(\Leftrightarrow \left[\begin{matrix} 3x=0\\ x+\frac{2}{3}=0\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=0\\ x=\frac{-3}{2}\end{matrix}\right.\)
d.
$x+\frac{1}{3}=\frac{2}{5}-(\frac{-1}{3})=\frac{2}{5}+\frac{1}{3}$
$\Leftrightarrow x=\frac{2}{5}$
Nguyễn Quý Trung:
\(x+\dfrac{1}{3}=\dfrac{2}{5}+\dfrac{1}{3}\)
Bạn bớt 2 vế đi 1/3 thì \(x=\dfrac{2}{5}\)
\(\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(\frac{-5}{12}\right)^3}=\frac{\frac{2^3}{3^3}.\frac{3^2}{4^2}.\left(-1\right)}{\frac{2^2}{5^2}.\frac{\left(-5\right)^3}{12^3}}=\)\(\frac{\frac{1}{6}.\left(-1\right)}{\frac{2^2}{5^2}.\frac{5^3}{2^6.3^3}.\left(-1\right)}=\frac{\frac{1}{2.3}}{\frac{5}{2^4.3^3}}=\frac{2^3.3^2}{5}=\frac{72}{5}\)
\(A=\left(100-1\right).\left(100-2^2\right).\left(100-3^2\right)...\left(100-50^2\right)\)
\(A=\left(100-1\right).\left(100-2^2\right).\left(100-3^2\right)......\left(100-10^2\right)......\left(100-50^2\right)\)
\(A=\left(100-1\right).\left(100-2^2\right).\left(100-3^2\right).....0......\left(100-50^2\right)\)
\(A=0\)
\(a.=\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{5}{3}+\dfrac{3}{2}+\dfrac{7}{3}-\dfrac{5}{2}=\dfrac{1+3-5}{2}-\dfrac{2+5-7}{3}=\dfrac{-1}{2}\)
\(b.\left(\dfrac{3}{4}-1\dfrac{1}{6}\right)^2:\sqrt{\dfrac{25}{144}}=\left(-\dfrac{5}{12}\right)^2:\dfrac{5}{12}=\dfrac{5}{12}\)
= (2^2 x 1/2^2) +(2^3 x 1/2^2)
=1+2
=3
học tốt nha bạn
4+ ( 8:4) =4 + 2 =6