Câu 1: Tính nhanh: a/ \(\dfrac{3}{11x12}\)+\(\dfrac{3}{12x13}\)+\(\dfrac{3}{13x14}\)+\(\dfrac{3}{14x15}\)
b/\(\dfrac{2}{2X3}\)+\(\dfrac{2}{3x4}\)+\(\dfrac{2}{4x5}\)+\(\dfrac{2}{5x6}\)
c/ \(\dfrac{3}{1x4}\)+\(\dfrac{3}{4x7}\)+\(\dfrac{3}{7x10}\)+................+\(\dfrac{3}{97x100}\)
d/ \(\dfrac{3}{2x5}\)+\(\dfrac{3}{5x8}\)+\(\dfrac{3}{8x11}\)+.............+\(\dfrac{3}{100x103}\)
e/ \(\dfrac{1}{1x5}\)+\(\dfrac{1}{5x10}\)+\(\dfrac{1}{10x15}\)+..................+\(\dfrac{1}{95x100}\)
Toán...
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Câu 1: Tính nhanh: a/ \(\dfrac{3}{11x12}\)+\(\dfrac{3}{12x13}\)+\(\dfrac{3}{13x14}\)+\(\dfrac{3}{14x15}\)
b/\(\dfrac{2}{2X3}\)+\(\dfrac{2}{3x4}\)+\(\dfrac{2}{4x5}\)+\(\dfrac{2}{5x6}\)
c/ \(\dfrac{3}{1x4}\)+\(\dfrac{3}{4x7}\)+\(\dfrac{3}{7x10}\)+................+\(\dfrac{3}{97x100}\)
d/ \(\dfrac{3}{2x5}\)+\(\dfrac{3}{5x8}\)+\(\dfrac{3}{8x11}\)+.............+\(\dfrac{3}{100x103}\)
e/ \(\dfrac{1}{1x5}\)+\(\dfrac{1}{5x10}\)+\(\dfrac{1}{10x15}\)+..................+\(\dfrac{1}{95x100}\)
Toán lớp 5 nha, giúp với mai mình học r, đúng mk tick cho.
a/ \(\dfrac{3}{11.12}+\dfrac{3}{12.13}+\dfrac{3}{13.14}+\dfrac{3}{14.15}\)
\(=3\left(\dfrac{1}{11.12}+\dfrac{1}{12.13}+\dfrac{1}{13.14}+\dfrac{1}{14.15}\right)\)
\(=3\left(\dfrac{1}{11}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{15}\right)\)
\(=3\left(\dfrac{1}{11}-\dfrac{1}{15}\right)\)
\(=\dfrac{4}{55}\)
b/ \(\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+\dfrac{2}{5.6}\)
\(=2\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}\right)\)
\(=2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\right)\)
\(=2\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\)
\(=\dfrac{2}{3}\)
c/ \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+.....+\dfrac{3}{97.100}\)
\(=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+....+\dfrac{1}{97}-\dfrac{1}{100}\)
\(=1-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
d/ \(\dfrac{3}{2.5}+\dfrac{3}{5.8}+.....+\dfrac{3}{100.103}\)
\(=\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+....+\dfrac{1}{100}-\dfrac{1}{103}\)
\(=\dfrac{1}{2}-\dfrac{1}{103}\)
\(=\dfrac{101}{206}\)
e/ Đặt :
\(A=\dfrac{1}{1.5}+\dfrac{1}{5.10}+....+\dfrac{1}{95.100}\)
\(\Leftrightarrow5A=\dfrac{5}{1.5}+\dfrac{5}{5.10}+....+\dfrac{5}{95.100}\)
\(=1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{10}+....+\dfrac{1}{95}-\dfrac{1}{100}\)
\(=1-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
\(\Leftrightarrow A=\dfrac{99}{100}:5=\dfrac{99}{500}\)
Dấu . là dấu nhân nhé <3
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