Question 5. The teacher wants to divide 87 students into teams which have the same number of students. Knowing that there must be more than one team, at least how many teams can be formed?
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VV
Vũ và Ngọc Anh
VIP
20 tháng 6 2023
8:4=2 (student)
So the teacher can divide the group of 8 students into 4 teams, each team has 2 students
BS
18 tháng 5 2015
Solution: We find the average of a team and a team prize was the third prize of a team score second. If the team won the first prize by winning three of the total points of the 5 teams are: 29 x 5 = 145 (point)> 144 points, not fulfilled. If the team more than the team's top prize, the third prize total 5 points greater than 145 team, also unsatisfactory. Thus the team must be less than the first prize team third prize. Then we put a team prize and a third team as a pair, the pair will have a total score of the two teams the second prize. Excess number third team (not rated pair with a team prize) is the point where total of 5 points less than 145. So the team of the three first prize more than the team how much they total of 5 145 teams will be smaller than they were. Because the total score of both teams was 144 points 5 team should score more than the third place team prize is 145-144 = 1.
TS
18 tháng 5 2015
Có 5 đội tham gia trong đội toán . Tổng số điểm là 144 điểm 5 đội bóng và thật thú vị khi 5 đội đã đạt được một trong ba giải thưởng : Best ( 30 điểm ) ; thứ hai ( 29 điểm ) ; Ba ( 28 điểm ) . Chứng minh các nhóm hơn đội giành được ba giải thưởng đầu tiên bên phải một đội bóng.
A. 3 teams
Question 5. The teacher wants to divide 87 students into teams which have the same number of students. Knowing that there must be more than one team, at least how many teams can be formed?
3 teams