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22 tháng 12 2017

(Ko chép lại đề nữa nhé, đánh đề bài xoắn cả tay)

\(P=\dfrac{\left(17,005-4,505\right)^2+125,075}{\left\{\left[0,1936:0,88+3,53\right]^2-7,5625\right\}:0,52}\)

\(=\dfrac{\left(12,5\right)^2+125,075}{\left\{\left[3,75\right]^2-7,5625\right\}:0,52}\)

\(=\dfrac{156,25+125,075}{\left\{14,0625-7,5625\right\}:0,52}\)

\(=\dfrac{281,325}{6,5:0,52}\)

\(=\dfrac{281,325}{12,5}\)

\(=22,506\)

\(Q=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{1016}{5}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)

\(=\dfrac{\left(\dfrac{1431}{108}-\dfrac{236}{108}-\dfrac{1170}{108}\right).\dfrac{1016}{5}+\dfrac{187}{4}}{\left(\dfrac{30}{21}+\dfrac{70}{21}\right):\left(\dfrac{259}{21}-\dfrac{300}{21}\right)}\)

\(=\dfrac{\dfrac{25}{108}.\dfrac{1016}{5}+\dfrac{187}{4}}{\dfrac{100}{21}:\dfrac{-1}{21}}\)

\(=\dfrac{\dfrac{1270}{27}+\dfrac{187}{4}}{-100}\)

\(=\dfrac{\dfrac{5080}{108}+\dfrac{5049}{108}}{-100}\)

\(=\dfrac{10129}{108}.\left(-\dfrac{1}{100}\right)\)

\(=-\dfrac{10129}{10800}\)

11 tháng 12 2017

hơi sai sai tki pGiang Thủy Tiên

13 tháng 12 2017

sai đề r bạn ơiiiii

3 tháng 2 2022

\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)

\(P=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)

\(P=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)

\(P=\dfrac{250}{\left(14,0625-7,5625\right):0,52}\)

\(P=\dfrac{250}{6,5:0,52}=\dfrac{250}{12,5}=20\)

\(P=\dfrac{\left(17.005-4.505\right)^2+125\cdot\dfrac{3}{4}}{\left(3.75^2-2.75^2\right):0.52}\)

\(=\dfrac{\left(12.5\right)^2+12.5\cdot\dfrac{15}{2}}{\left(3.75+2.75\right):0.52}\)

\(=\dfrac{12.5\left(12.5+7.5\right)}{6.5:0.52}=\dfrac{12.5\cdot20}{12.5}=20\)

18 tháng 8 2020

\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left[\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75\right)^2\right]:\frac{13}{25}}\)

\(=\frac{\left(\frac{10203}{125}.\frac{3}{16}-\frac{901}{200}\right)+\frac{503}{4}}{\left[\left(\frac{121}{625}.\frac{25}{2}+\frac{353}{100}\right)^2-\frac{121}{16}\right].\frac{25}{13}}\)

\(=\frac{\left(15,3045-\frac{901}{200}\right)+\frac{503}{4}}{\left(\frac{14161}{400}-\frac{121}{16}\right).\frac{25}{13}}\)

\(=\frac{136,5495}{\frac{696}{13}}\)

\(=2,550493534\)