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15 tháng 8 2017

6. If he didn’t sit around too much, he’d be fit.

7. If Carol hadn’t been studying, she’d have answered the phone.

8. If Rita had got some sleep last night, she wouldn’t be exhausted today.

9. If she wasn’t too thin, she wouldn’t feel cold so much.

10. If he polished his shoes, he’d look smart.

11. If he could park near his office, he’d come by car.

12. If my house was guarded by two big dogs, it’d be broken into every night.

13. If the flats were clearly numbered, it’d be easy to find.

14. If I knew her e-mail address, I could tell you.

15. If she didn’t work in the evening, she’d have time to play with her children.

16. They’d be upset if I told them what happened.

17. If I were tall enough, I would join the basketball team.

18. If he saw the signal, he’d stop his car.

19. If Peter prepared his lessons well, he wouldn’t get bad marks.

20. If Mary had enough money, she’d buy a new car.

21. If you don’t go right now, you’ll be late for the train.

22. If he had enough qualifications, he’d apply for the job.

23. If we don’t hurry, we’ll be late for the exam.

24. If you often talked to them, they’d understand you.

25. If you spoke English naturally, they’d
understand you.

6 tháng 12 2021

Lm hộ tui với

 

 

 

a: Xét ΔMNK và ΔEPK có 

KM=KE

\(\widehat{MKN}=\widehat{EKP}\)

KN=KP

Do đó: ΔMNK=ΔEPK

15 tháng 7 2021

1 C

2 D

3 D

4 D

5 C

6 D

7 C

8 D

9 C

10 B

Ăn gì chưa

13 tháng 7 2021

Bài 6 : 

$a) H_2SO_4 + BaCl_2 \to BaSO_4 + 2HCl$
$b) CaCO_3 + 2HNO_3 \to Ca(NO_3)_2 + CO_2 + H_2O$
$c) 2KOH + 2NaHSO_4  \to Na_2SO_4 + K_2SO_4 + 2H_2O$

$d) CuO + 2HCl \to CuCl_2 + H_2O$
$e) SO_2 + NaOH \to NaHSO_3$
$g) CO_2 + 2NaOH \to Na_2CO_3 + H_2O$

Câu 7 : 

CTHH lần lượt là : $HBr,H_2SiO_3,HMnO_4,H_2Cr_2O_7$

13 tháng 7 2021

Bài 8 : 

Gọi CTHH là $H_xN_yO_z$

$\%O = 67,995\%$

Ta có :

$x : y : z = \dfrac{2,218}{1} : \dfrac{29,787}{14} : \dfrac{67,996}{16} = 1 : 1 : 2$

Vậy X là $HNO_2$(axit nitrit)$

Câu 1:

Ta có: \(0,1+0,2+...+0,19+0,20\)

\(=\left(0,1+0,2+...+0,10\right)+\left(0,11+0,12+...+0,19+0,20\right)\)

\(=4.6+1.55=6,15\)

NV
13 tháng 12 2021

\(4sin^2x-2\left(\sqrt{3}+\sqrt{2}\right)sinx+\sqrt{6}=0\)

\(\Leftrightarrow4sin^2x-2\sqrt{3}sinx-2\sqrt{2}sinx+\sqrt{6}=0\)

\(\Leftrightarrow2sinx\left(2sinx-\sqrt{3}\right)-\sqrt{2}\left(2sinx-\sqrt{3}\right)=0\)

\(\Leftrightarrow\left(2sinx-\sqrt{3}\right)\left(2sinx-\sqrt{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}sinx=\dfrac{\sqrt{3}}{2}\\sinx=\dfrac{\sqrt{2}}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{3}+k2\pi\\x=\dfrac{2\pi}{3}+k2\pi\\x=\dfrac{\pi}{4}+k2\pi\\x=\dfrac{3\pi}{4}+k2\pi\end{matrix}\right.\)