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a: \(=\dfrac{32}{48}\cdot\dfrac{50}{75}=\dfrac{2}{3}\cdot\dfrac{2}{3}=\dfrac{4}{9}\)
b: \(=\dfrac{7\cdot9\cdot81}{27\cdot5\cdot84}=\dfrac{9\cdot81}{27\cdot3}\cdot\dfrac{7}{5\cdot28}=9\cdot\dfrac{1}{4\cdot5}=\dfrac{9}{20}\)
\(a,\dfrac{8\times4\times50}{48\times75}=\dfrac{2\times2\times2\times2\times2\times25}{2\times2\times2\times2\times3\times25\times3}=\dfrac{2\times2}{3\times3}=\dfrac{4}{9}\)
\(b,\dfrac{7\times9\times81}{9\times3\times5\times84}=\dfrac{7\times9\times9\times3\times3}{9\times3\times5\times7\times3\times4}=\dfrac{9}{5\times4}=\dfrac{9}{20}\)
`5/9xx1/4+4/9xx3/12`
`=5/9xx1/4+4/9xx1/4`
`=1/4xx(5/9+4/9)`
`=1/4xx9/9`
`=1/4xx1`
`=1/4`
a: =20/90+15/90+54/90=89/90
b: =(9/13+4/13)+2/3=1+2/3=5/3
a, \(=\dfrac{1+4}{5}+\dfrac{5+1+3}{9}=1+1=2\)
b, \(=\dfrac{1+4+2}{3}+\dfrac{1+2+5}{6}=\dfrac{6}{3}+\dfrac{8}{6}=2+\dfrac{4}{3}=\dfrac{6+4}{3}=\dfrac{10}{3}\)
\(=\dfrac{3}{7}\left(\dfrac{5}{4}-\dfrac{2}{9}\right)=\dfrac{3}{7}\cdot\dfrac{45-8}{36}=\dfrac{3}{36}\cdot\dfrac{37}{7}=\dfrac{37}{84}\)
\(\dfrac{3}{7}:\dfrac{4}{5}-\dfrac{3}{7}:\dfrac{9}{2}\)
\(=\dfrac{3}{7}\times\dfrac{5}{4}-\dfrac{3}{7}\times\dfrac{2}{9}\)
\(=\dfrac{3}{7}\times\left(\dfrac{5}{4}-\dfrac{2}{9}\right)\)
\(=\dfrac{3}{7}\times\left(\dfrac{45}{36}-\dfrac{8}{36}\right)\)
\(=\dfrac{3}{7}\times\dfrac{37}{36}\)
\(=\dfrac{37}{84}\)
#DatNe
\(x=\dfrac{3}{4}-\dfrac{1}{8}\)\(\)
\(x=\dfrac{6}{8}-\dfrac{1}{8}\)
\(x=\dfrac{5}{8}\)
\(=\dfrac{2}{5}x\left(\dfrac{9}{4}-\dfrac{5}{4}\right)\)
\(=\dfrac{2}{5}x1\)
\(=\dfrac{2}{5}\)
\(\dfrac{63\times81}{135\times84}\text{=}\dfrac{3\times3\times7\times3\times3\times3\times3}{3\times3\times3\times5\times2\times2\times3\times7}\text{=}\dfrac{9}{20}\)
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