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1) 39×51+39×49=39x(51+49)=39x100=3900
2. phân tích 100 thành 50 r lm như câu 1
1. = 39 x (51 + 49)
= 39 x 100
= 3900
2. = 50 x 2 x 31 + 100 x 19
= 100 x 31 + 100 x 19
= 100 x (31 + 19)
= 100 x 50
= 5000
![](https://rs.olm.vn/images/avt/0.png?1311)
Số số hạng của S₁:
(51 - 1) : 2 + 1 = 26 (số)
Số số hạng của S₂:
(153 - 47) : 2 + 1 = 54 (số)
S₁ = (51 + 1) . 26 : 2 = 676
S₂ = -(153 + 47) . 54 : 2 = -5400
⇒ S₁ + S₂ = 676 + (-5400) = -4724
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1: =29-16-3*2=13-6=7
2: =35-12+(-14)-2
=23-16=7
3: =4*3125-32:16
=12500-2
=12498
4: =-452+67-75+452=-8
5: =18+99*18-3^5-2^5
=1800-275
=1525
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\(91.51+49.163+49.72\)
\(=91.51+49.\left(163+72\right)\)
\(=91.51+49.235\)
\(=4641+11515\)
\(=16156\)
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-5 + (-37 - 45 + 51) - (-37 + 51)
= -5 - 37 - 45 + 51 + 37 - 51
= - (5 + 45) - (37 - 37) + (51 - 51)
= - 50 - 0 + 0
= - 50
- (15 - 47 + 58) + (15 - 47 ) + 3
= - 15 + 47 - 58 + 15 - 47 + 3
= (-15 + 15) + (47 - 47) - (58 - 3)
= 0 + 0 - 55
= - 55
(53 - 45 - 49) - (53 + 45 - 49)
= 53 - 45 - 49 - 53 - 45 + 49
= (53 - 53) + (-49 + 49) - (45 + 45)
= 0 + 0 - 90
= - 90
13 - 15 + 49 - 13 + 15 - 48
= (13 - 13) + (-15 + 15) + (49 - 48)
= 0 + 0 + 1
= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\( 49.(51 - 4) - 51.(49 + 4)\)
\(=49.51-49.4-51.49-51.4\)
\(=49.(51-4-51)-51.4\)
\(=49.(-4)-51.4\)
\(=4.(-49-51)\)
\(=4.(-100)\)
\(=-400\)
b)
\( 71.64 + 32.(-7) - 13.32\)
\(=71.32.2+32.(-7)-13.32\)
\(=142.32+32.(-7)-13.32\)
\(=32.(142-7-13)\)
\(=32.122\)
\(=3904\)
c)
\( 11 + (-13) + 15 + (-17) + ... + 59 + (-61)\)
\(=(-2)+(-2)+...+(-2)\)
\(=(-2).13\)
\(=-26\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a. 49.51- 49.4 -51.49 -51.4
= -49.4 - 51.4
=4.(-49-51)
=4.-100
=-400
b.71.64 + 32.(-7) -13.32
= 71.64 + 32.(-7-13)
=71.64 + 32.-20
=71.32.2 +32.-20
=32.(71x2-20)
=32. 122
= 3904
c. (11-13)+(15-17)+..+(59-61)
=-2 x 13
=-26
![](https://rs.olm.vn/images/avt/0.png?1311)
f: =49*51-49*4-51*49-51*4
=-49*5-51*4
=-4*100=-400
h: =41(-328+128)
=-41*200
=-8200
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29/19.49/51+29/19.34/51-29/19.32/51
=29/19.(49/51+34/51-32/51)
=29/19.1
=29/19
\(\dfrac{29}{19}.\dfrac{49}{51}+\dfrac{29}{19}.\dfrac{34}{51}-\dfrac{29}{19}.\dfrac{32}{51}\)
\(=\dfrac{29}{19}.\left(\dfrac{49}{51}+\dfrac{34}{51}-\dfrac{32}{51}\right)\)
\(=\dfrac{29}{19}.1\)
\(=\dfrac{29}{19}\)
135.(49+51)-35.(51+49)
= 135.100-35.100
=(135-35).100
= 100.100
= 10000
135.(49+51) - 35.(51+49)
135.100 - 35.100
100.(135-35)
100.100
10000